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statuscvo [17]
3 years ago
8

Correctness the relation Where pressure=3accleration due to gravity/4pi G​

Physics
1 answer:
Inessa05 [86]3 years ago
7 0

Explanation:

given expression, \rho=\frac{3g}{4rG}ρ=

4rG

3g

where \rhoρ is density , g is acceleration due to gravity , r is radius and G is universal gravitational constant.

dimension of \rhoρ = [ML^-3]

dimension of g = [LT^-2]

dimension of r = [L]

dimension of G = [M^-1L^3T^-2]

expression will be dimensionally correct,

dimension of \rhoρ = dimension of {g/rG}

LHS = dimension of \rhoρ = [ML^-3]

RHS = dimension of {g/rG} = dimension of g/dimension of r × dimension of G

= [LT^-2]/[L][M^-1L^3T^-2]

= [ML^-3]

here, LHS = RHS

so, expression is dimensionally correct.

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A ball is bouncing to a height that is 1/3 of the previous height after every bounce. What kind of sequence is this? How could y
tamaranim1 [39]

Answer and Explanation:

The ball is bouncing to a height of 1/3 of its previous height this is a type of geometric sequence the total distance can be found by the sum of geometric sequence

For example let the initial height is 243 fit

After one bounce it will reach  243/3 =81 feet

After second bounce 81/3=27 feet

After third bounce 27/3 =9 feet

After fourth bounce 9/3 =3 feet

So a sequence is formed that is 243,81,27,9,3..........

Here r=\frac{3}{9}=\frac{1}{3}

Sum of infinite GP = \frac{a}{1-r}

From this formula we can find the total distance traveled by the ball

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What is a landform created by plate motion?
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Explanation:

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A 6 cm long spring extends to 9 cm when a 1 kg load is suspended from it. What would be its length if a 2 kg load were suspended
Ganezh [65]
The answer is D that is the right question
8 0
3 years ago
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masha68 [24]
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7 0
3 years ago
Dragsters can actually reach a top speed of 145.0 m/s in only 4.45 s. (a) Calculate the average acceleration for such a dragster
astraxan [27]

Answer:

a) 32.58 m/s²

b) 161.84 m/s

Explanation:

Initial velocity = u = 0

Final velocity = v = 145 m/s

Time taken = t = 4.45 s

s = Displacement of dragster = 402 m

a = Acceleration

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{145-0}{4.45}\\\Rightarrow a=32.58\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as-u^2}\\\Rightarrow v=\sqrt{2\times 32.58\times 402-0^2}\\\Rightarrow v=161.84\ m/s

The final velocity is greater than the velocity used to find the average acceleration due to the gear changes. The first gear in a dragster has the most amount of toque which means the acceleration will be maximum. The final gears have less torque which means the acceleration is lower here. The final gears have less acceleration but can spin faster which makes the dragster able to reach higher speeds but slowly.

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