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statuscvo [17]
3 years ago
8

Correctness the relation Where pressure=3accleration due to gravity/4pi G​

Physics
1 answer:
Inessa05 [86]3 years ago
7 0

Explanation:

given expression, \rho=\frac{3g}{4rG}ρ=

4rG

3g

where \rhoρ is density , g is acceleration due to gravity , r is radius and G is universal gravitational constant.

dimension of \rhoρ = [ML^-3]

dimension of g = [LT^-2]

dimension of r = [L]

dimension of G = [M^-1L^3T^-2]

expression will be dimensionally correct,

dimension of \rhoρ = dimension of {g/rG}

LHS = dimension of \rhoρ = [ML^-3]

RHS = dimension of {g/rG} = dimension of g/dimension of r × dimension of G

= [LT^-2]/[L][M^-1L^3T^-2]

= [ML^-3]

here, LHS = RHS

so, expression is dimensionally correct.

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How many neutrons are contained in 2 kg? Mass of one neutron is 1.67x10-27 kg.
pav-90 [236]

Answer:

1.2 × 10^27 neutrons

Explanation:

If one neutron = 1.67 × 10^-27 kg

then in 2kg...the number of neutrons

; 2 ÷ 1.67 × 10^-27

There are.... 1.2 × 10^27 neutrons

8 0
3 years ago
When we look up at the stars, we are seeing the future", is this astronomer correct ? Why or why not ?
Andrei [34K]

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if the stars connect to a thing, then it describes.

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What is life like in a cave camp? Do you think you would like to experience this? Why or why not?
GalinKa [24]

Answer:

There's no risk of animals or bad weather interfering with your campsite, either. You don't even really need a tent. A sleeping pad, sleeping bag and a mindful eye to pick up everything you brought in is all you really need to enjoy overnight caving. Do your research

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3 0
3 years ago
Outside the space shuttle, you and a friend pull on two ropes to dock a satellite whose mass is 700 kg. The satellite is initial
MaRussiya [10]

Answer:

your friend did a work of 1717.34 J

Explanation:

The sum of the work made by your friend and you is equal the change in the kinetic energy, so:

W_a+W_b=\frac{1}{2}mv_f^{2}-\frac{1}{2}mv_i^{2}

Where W_a is the work that you did, W_b is the work that your friend did, m is the mass of the satellite and v_f and v_i are the final and initial speeds

Additionally the work that you did is equal to:

W_a=F.s

Where F and s are vectors. So, the vector s that said the displacement is calculated as:

s = <2.3, 2.6, -11.8> - <3.3, -1.6, 2.0>

s = <-1 , 4.2 , -13.8>

Therefore, W_a is:

W_a=.

W_a=(-400*-1)+(500*4.2)+(250*-13.8)\\W_a=400+2100-3450\\W_a=-950

Then, replacing the values on initial equation and solving for W_b, we get:

-950+W_b=\frac{1}{2}(700)(6.18)^{2}-\frac{1}{2}(700)(6)^{2}\\-950+W_b=767.24\\W_b=767.24+950\\W_b=1717.34J

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3 years ago
A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct expression for the gravitational
Naya [18.7K]

Answer: B. The gravitational field strength of Planet X is Wx/m.

Explanation:

Weight is a force, and as we know by the second Newton's law:

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Force equals mass times acceleration.

Then if the weight is:

Wx, and the mass is m, we have the equation:

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Wx/m = a

Then the correct option is:

B. The gravitational field strength of Planet X is Wx/m.

4 0
3 years ago
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