29. Cross-contamination occurs when

A Question Pre

lana66690 [7]

Answer:

A present

Explanation:

Because if the facts

7 0

3 years ago

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Find the wavelength of a photon of light with energy of 9.02x10^-19 J.

vitfil [10]

Answer:

2.21 x 10⁻⁷m⁻¹

Explanation:

Given parameters:

Energy of the photon = 9.02 x 10⁻¹⁹J

Unknown:

Wavelength of the photon = ?

Solution;

The wavelength and energy of a photon are related using the expression below;

E = $\frac{hc}{wavelength}$

h is the Planck's constant = 6.63 x 10⁻⁴m²kg/s²

c is the speed of light

E is the energy

h c = E x wavelength

Wavelength = $\frac{hc}{E}$ = $\frac{6.63 x 10^{-34} x 3 x 10^{8} }{9.02 x 10^{-19} }$

Wavelength = 2.21 x 10⁻⁷m⁻¹

8 0

3 years ago

A student wishes to prepare 25mL of 0.1M NaOH from 6M NaOH.

liraira [26]

Answer:

Na(OH)4

Explanation:

Look at the charges and add them up

Na(OH) Na(OH)

7 0

3 years ago

A certain kind of light has a wavelength of 4.6 micrometers what is the frequency of this light and gigahertz? Use c= 2.998 × 10

Leno4ka [110]

Answer:

6.52×10⁴ GHz

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 4.6 μm

Velocity of light (v) = 2.998×10⁸ m/s

Frequency (f) =?

Next we shall convert 4.6 μm to metre (m). This can be obtained as follow:

1 μm = 1×10¯⁶ m

Therefore,

4.6 μm = 4.6 μm × 1×10¯⁶ m / 1 μm

4.6 μm = 4.6×10¯⁶ m

Next, we shall determine frequency of the light. This can be obtained as follow:

Wavelength (λ) = 4.6×10¯⁶ m

Velocity of light (v) = 2.998×10⁸ m/s

Frequency (f) =?

v = λf

2.998×10⁸ = 4.6×10¯⁶ × f

Divide both side by 4.6×10¯⁶

f = 2.998×10⁸ / 4.6×10¯⁶

f = 6.52×10¹³ Hz

Finally, we shall convert 6.52×10¹³ Hz to gigahertz. This can be obtained as follow:

1 Hz = 1×10¯⁹ GHz

Therefore,

6.52×10¹³ Hz = 6.52×10¹³ Hz × 1×10¯⁹ GHz / 1Hz

6.52×10¹³ Hz = 6.52×10⁴ GHz

Thus, the frequency of the light is 6.52×10⁴ GHz

5 0

3 years ago

what is the relationship between the scale divisions marked on the graduated cylinders and the estimated uncertainty in the volu

AURORKA [14]

Answer:

The relationship between the scale divisions marked on the graduated cylinders and the estimated uncertainty in the volume measurements is that the larger the divisions the larger the uncertainty, and the smaller the divisions the smaller the uncertaintity.

Explanation:

In general, graduated cylinders are marked with divisions (lines) at equal spaces or intervals. There are divisions that show the measure with a number and a series of intermediate not numbered divisions in between two numbered lines.

The uncertainty of the instrument is determined as half the difference between two consecutive marks.

So, the larger the interval of two consecutive marks the larger the uncertainty.

The attached image, taken from brainly.com/question/13102373, shows you some marks in a graduated cylinder.

7 0

3 years ago