Ask question

Ask question

All categories

3 years ago

5

Why does a water molecule have a bent shape?

1 answer:

a_sh-v [17]3 years ago

3 0

The 2 lone electron pairs exerts a little extra repulsion on the two bonding hydrogen atoms to create a slight compression to a 104obond angle. The water molecule is bent molecular geometry because the lone electron pairs, although still exerting influence on the shape, are invisible when looking at molecular geometry.

You might be interested in

Which of the following is/are part of the nitrogen cycle?

Pachacha [2.7K]

Denitrification is part of the nitrogen cycle

7 0

3 years ago

How to tell the difference between polar and nonpolar covalent bonds?

NemiM [27]

You need to look at the electronegativity and decide wheter the difference of both of the numbers are significant enough to form a polar bond

3 0

3 years ago

What is the mass number of an atom that has six protons , six electrons and eight neutrons

Tresset [83]

Answer:

14

Explanation:

Given parameters:

Number of protons = 6

Number of electrons = 6

Number of neutrons = 8

Unknown:

Mass number = ?

Solution:

The mass number of an atom is the sum of protons and neutrons in an atom;

Mass number = number of protons + number of neutrons

Mass number = 6 + 8 = 14

7 0

3 years ago

What is the element found in Group 17 Period 4?

faust18 [17]

Answer:

Bromine is found in Group 17, Period 4 on the periodic table.

3 0

3 years ago

PLEASE HELP!! I REALLY NEED HELP

Allushta [10]

Answer:

Explanation:

1. find the molar mass (amu) of each element and add them to get the whole molar mass.

2. divide the 1 element molar mass with the whole molar mass

3. multiple by 100 and that gives you the % composition.

<h2><u><em>56-57: NaCl</em></u></h2>

1. Na(22.99amu) + Cl (35.453amu)=58.443

2(Na): $\frac{22.99}{58.443}$ = .393

2(Cl): $\frac{35.453}{58.443}$ = .607

3(Na): .393 * 100=39.3%

3(Cl): .607 * 100= 60.7%

<h2><u>58-60 </u> $K_{2} CO_{3}$ <u /></h2>

1. K: (39.098)(2)=78.196

_ C: (12.011)(1)= 12.011

_O: (15.99)(3) = 47.997

78.196+12.011+47.997= 138.204

2:K: $\frac{78.196}{138.204}$ = .566 <u>Step </u>3: (.566)(100)= 56.6%

2: C: $\frac{12.011}{138.204}$ = .087 <u>Step 3</u>: (.087)(100)= 8.7%

2: O: $\frac{47.997}{138.204}$ = .347 <u>Step 3</u>: (.347)(100) = 34.7%

<h2>61-62 $Fe_{3} O_{4}$ </h2>

1. Fe (55.845)(3)= 167.535

_ O (15.999)(4) = 63.996

167.535+63.996=231.531

2: Fe: $\frac{167.535}{231.531}$ = .724 Step 3: (.724)(100)= 72.4%

2: O : $\frac{63.996}{231.531}$ = .276 Step 3: (.276)(100) = 27.6%

<h2>63-65 $C_{3}H_{5}(OH)_{3}$ </h2>

1.

C(12.011*3)=36.033

H(1.008*5)=5.04 + (1.008*3)=3.024 so its 8.064

O(15.999*3)=47.997

add them: 92.094

2: C: $\frac{36.033}{92.094}$ = .391 Step 3: (.391)(100) = 39.1%

2: H: $\frac{8.064}{92.094}$ = .088 step 3: (.088)(100) = 8.8%

2: O: $\frac{47.997}{92.094}$ = .521 step 3: (.521)(100) = 52.1%

3 0

3 years ago