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viva [34]
3 years ago
12

What is the percentage of lithium in lithium carbonate (Li2CO3)?

Chemistry
2 answers:
eduard3 years ago
8 0

The correct answer is

18.78%

:)

ale4655 [162]3 years ago
6 0
Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol Li = 6.94*2 = 13.88g


% LI = 13.88/73.89*100 = 18.78% perfectly correct.
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If the percent (mass/mass) for a solute is 8% and the mass of the solution is 200 g, what is the mass of solute in solution?
tatyana61 [14]

Answer:

The answer to your question is  16 g

Explanation:

Data

Percent by mass = 8%

Mass of the solution = 200 g

Mass of solute = ?

Formula

Percent by mass = mass of solute / mass of solution x 100

- Solve for mass of solute

  Mass of solute = Percent by mass x mass of solution / 100

- Substitution

   Mass of solute = 8 x 200 / 100

- Simplification

    Mass of solute = 1600 / 100

- Result

    Mass of solute = 16 g

3 0
3 years ago
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Answer:

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Explanation:

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vodomira [7]
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4 years ago
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Gala2k [10]

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false

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6 0
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