Law of Definite Proportions
The mass of NCl3 in 4.00 moles of NCl3 is 481.44 grams
Mole is defined as the amount of the substance containing the same number of discrete entities (atoms, molecules, ions, etc) as there are atoms in a sample of pure 12C weighing exactly 12g. The number of particles present in one mole of any substance =Avogadro Number=6.
The formula for number mole is given as:
Number of moles = <u>Mass of the substance </u> ; Now substituting the values
Molar mass
⇒ 4.00 = <u>x </u> [Molar mass of NCl3 = 120.36]
120.36
⇒ x = 4.00 × 120.36
⇒ x = 481.44 grams
Therefore the mass of NCl3 is 481.44 grams
To know more about mole concept
brainly.com/question/23059935
#SPJ1
Answer:
The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ
Explanation:
<u>Step 1: </u>The balanced equation
CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g) ΔH = -802 kJ
<u>Step 2:</u> Given data
We notice that for 1 mole of methane (CH4), we need 2 moles of O2 to produce : 1 mole of CO2 and 2 moles of H20.
The enthalpy change of combustion, given here as Δ
H
, tells us how much heat is either absorbed or released by the combustion of <u>one mole</u> of a substance.
In this case: we notice that the combustion of 1 mole of methane gives off (because of the negative number), 802.3 kJ of heat.
<u>Step 3: </u>calculate the enthalpy change for 3 moles
The -802 kj is the enthalpy change for 1 mole
The change in enthalpy for 3 moles = 3* -802 kJ = -2406 kJ
The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ
Actualy the answer is Lower pressure causes the papers to come closer together.
Please mark brainiest if this is correct and helpful.
