Answer:
a ) 2.368 rad/s
b) 3.617 rad/s
Explanation:
the minimum angular velocity that Prof. Stefanovic needs to spin the bucket for the water not to fall out can be determined by applying force equation in a circular path
i.e
------ equation (1)
where;
Also
since; that is the initial minimum angular velocity to keep the water in the bucket
Now; we can rewrite our equation as :
So; Given that:
The rope that is attached to the bucket is lm long and his arm is 75 cm long.
we have our radius r = 1 m + 75 cm
= ( 1 + 0.75 ) m
= 1.75 m
g = acceleration due to gravity = 9.81 m/s²
Replacing our values into equation (2) ; we have:
b) if he detaches the rope and spins the bucket by holding it with his hand ; then the radius = 0.75 m
∴
If an object is consist of a negative acceleration or
composed of it, it is likely engaging of having to accelerate in a certain
direction in which the direction is heading towards the opposite of the
direction that is stated and that is likely to be a positive direction.
1 Days to Seconds = 86400 70 Days to Seconds = 6048000
2 Days to Seconds = 172800 80 Days to Seconds = 6912000
3 Days to Seconds = 259200 90 Days to Seconds = 7776000
4 Days to Seconds = 345600 100 Days to Seconds = 8640000
Answer:
Explanation:
This problem is based on conservation of angular momentum.
moment of inertia of larger disc I₁ = 1/2 m r² , m is mass and r is radius of disc . I
I₁ = .5 x 20 x 5²
= 250 kgm²
moment of inertia of smaller disc I₂ = 1/2 m r² , m is mass and r is radius of disc . I
I₂ = .5 x 10 x 2.5²
= 31.25 kgm²
3500 rmp = 3500 / 60 rps
n = 58.33 rps
angular velocity of smaller disc ω₂ = 2πn
= 2π x 58.33
= 366.3124 rad /s
applying conservation of angular momentum
I₂ω₂ = ( I₁ +I₂) ω , ω is the common angular velocity
31.25 x 366.3124 = ( 250 +31.25) ω
ω = 40.7 rad / s .
Speed = Distance%Time
Speed is 0,4km/h
