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frozen [14]
3 years ago
10

Final exam answers for physical science apex?

Physics
1 answer:
Tju [1.3M]3 years ago
4 0
First table:

1. For height, we usually use cm. If it is a must to use the conversion to solve for number 1, we can first convert the ft into m then to cm and then convert the in to cm and then add the values.

5ftx\frac{0.305m}{1ft}  = 1.525mx\frac{100cm}{1m} =152.5cm

then we convert the remaining 2in into cm and add it up:
2inx\frac{2.54cm}{1in}=5.08cm

152.5cm + 5.08cm = 157.58cm or 157.6cm

Another way to do this is to convert the ft to in and add it up to the remaining 2 in then convert to cm. The answer would be more or less the same. 

2. For weight, we will convert lbs to kg. 

105lbsx\frac{1kg}{2.2lbs} =  \frac{105kg}{2.2} = 47.7kg

3. For distance we will convert mi to km. 

1.1mix\frac{1.61km}{1mi} = 1.8km

4. The unit mph is miles per hour and we will want to convert that into kph or kilometers per hour. You will use the same method that you did above to get it. We do not need to convert hours anymore, so it will stay as is.

65 \frac{mi}{hr}x\frac{1.61km}{1mi} = 104.7\frac{km}{hr}

5. Now for the next one it is very straightforward because 1V = 1V no matter where you go. So if the given is 220V then that means that the converted value is also 220V. 

6. Now to convert Fahrenheit to Celsius, then all you have to do is use the formula given above and fill in what you know. 

The given is  70°F

°C = \frac{5}{9} (F - 32)
     = \frac{5}{9} (70 - 32)
     = \frac{5}{9} (38)
     = \frac{190}{9}
     = 21.1°C

The second table is very easy, all you need to do is convert the values to scientific notation or the other way around. All you need to do is move the decimal till you have a coefficient that is between 1 to 10 and then count how many times you moved the decimal. That will be the number or the exponent of 10. 

1. $150,000 = $1.5 x 10^5

If you moved the decimal to the left, the exponent will be positive. 

Now the other way around. To convert scientific notation to standard form, just move the decimal the number of places indicated by the exponent of 10. If it is positive, you will move to the right and if it is negative, you will move to the left. 

2. 2.59x10^6 = 2,590,000m

Now notice that the next value is less than 1. This means you will be moving the the decimal to the right to make it have a coefficient of 1 to 10. You need to move it 3 times to the right so that means the exponent will be negative. 

3. 0.005in = 5.0 x 10^(-3)in

Now do not forget to put in your units. In math or even in science the unit is EXTREMELY IMPORTANT. 

Hope this helped you and good luck!
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A parallel-plate air capacitor with a capacitance of 260 pF has a charge of magnitude 0.155 μC on each plate. The plates have a
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Answer:

The potential difference between the plates is 596.2 volts.

Explanation:

Given that,

Capacitance C=260\ pF

Charge q=0.155\ \mu\ C

Separation of plates = 0.313 mm

We need to calculate the potential difference between the plates

Using formula of potential difference

V= \dfrac{Q}{C}

Where, Q = charge

C = capacitance

Put the value into the formula

V=\dfrac{0.155\times10^{-6}}{260\times10^{-12}}

V=596.2\ volts

Hence,The potential difference between the plates is 596.2 volts.

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Two protons are released from rest when they are 0.720 nm apart. For related problem-solving tips and strategies, you may want t
Gnesinka [82]

Answer:

a) Speed of the electrons at maximum speed = (1.384 × 10⁴) m/s

The maximum speed occurs at the point where all of the initial potential energy is converted into kinetic energy.

b) Maximum acceleration of the protons = (2.660 × 10¹⁷) m/s²

The maximum acceleration occurs at the minimum distance apart for the two protons.

Explanation:

The maximum speed occurs when all the potential energy of the protons has been converted to kinetic energy.

The potential energy between the two protons at the instant of release is given by

U = (kq₁q₂/r)

k = Coulomb' s constant = (8.988 × 10⁹) Nm²/C²

q₁ = q₂ = charge on a proton = q = (1.602 × 10⁻¹⁹) C

r = separation between the two protons = 0.72 nm = (7.2 × 10⁻¹⁰) m

U = (kq²/r) = [(8.988 × 10⁹) × (1.602 × 10⁻¹⁹)²] ÷ (7.2 × 10⁻¹⁰) = (3.204 × 10⁻¹⁹) N/m or Joules

At the maximum speeds, the two protons will not possess any potential Energy, only kinetic energy.

The sum of kinetic and potential energies is always constant for the system

(Initial Kinetic Energy) + (Initial Potential Energy) = (Kinetic Energy at maximum speed) + (Potential Energy at maximum speed)

Initial Kinetic Energy of the system = 0 J (Since both protons were intially at rest)

Initial Potential Energy = (3.204 × 10⁻¹⁹) J

Kinetic Energy at maximum speed = Sum of the kinetic energies of the protons at this point = (½mv²) + (½mv²) = (mv²) J (Since theu are both protons, they have the same mass and the same speed at maximum speed)

Potential Energy at maximum speed = 0 J

0 + (3.204 × 10⁻¹⁹) = mv² + 0

mv² = (3.204 × 10⁻¹⁹)

m = mass of a proton = (1.673 × 10⁻²⁷) kg

v = speed of each of the protons at maximum speed = ?

v = √[(3.204 × 10⁻¹⁹) ÷ m]

v = √[(3.204 × 10⁻¹⁹) ÷ (1.673 × 10⁻²⁷)]

v = √(1.915 × 10⁸) = 13,838.8 m/s = (1.384 × 10⁴) m/s

b) Since the two protons repel each other and force of repulsion reduces as the dI stance between the protons increases, the maximum acceleration occurs at the minimum distance apart for the two protons.

Force of repulsion acting on each proton is given through Coulomb's law as

F = (kq₁q₂/r²)

And the force acting on each proton is obtainable using Newton's law that

F = ma

So, the acceleration of each proton at any time is obtainable through a relation of these 2 formulas.

ma = (kq₁q₂/r²)

a = (kq₁q₂/r²m)

k = Coulomb' s constant = (8.988 × 10⁹) Nm²/C²

q₁ = q₂ = charge on a proton = q = (1.602 × 10⁻¹⁹) C

r = separation between the two protons = 0.72 nm = (7.2 × 10⁻¹⁰) m

m = mass of a proton = (1.673 × 10⁻²⁷) kg

a = [(8.988 × 10⁹) × (1.602 × 10⁻¹⁹)²] ÷ [(7.2 × 10⁻¹⁰)² × (1.673 × 10⁻²⁷)]

a = (2.660 × 10¹⁷) m/s²

Hope this Helps!!!

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Answer:

In free fall, mass is not relevant and there's no air resistance, so the acceleration the object is experimenting will be equal to the gravity exerted. If the object is falling on our planet, the value of gravity is approximately 9.81ms2 .

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A student measures the mass 8cm block of brown sugar to be 12.9g. what is the density of the brown sugar.
antoniya [11.8K]

Correction

A student measures the mass <em><u>8cm3</u></em> block of brown sugar to be 12.9g. what is the density of the brown sugar

Answer:

1.6\ g/cm^{3}

Explanation:

Density is defined as mass per unit volume of an object expressed as \rho=\frac {m}{v} where \rho is the density, m is the mass of sugar and v is the volume of the sugar. Considering that the volume is given as 8cm3 for sugar then we substitute this for v and mass of 12.9 g we substitute for g then the density will be

\rho=\frac {12.9 g}{8 cm3}=1.6125\ g/cm^{3}\approx 1.6\ g/cm^{3}

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