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Ugo [173]
3 years ago
10

Find 4/1 point from b to a a(-4,-7) b(12,5)

Mathematics
1 answer:
erastovalidia [21]3 years ago
7 0
I would say the answer is B
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Which of the following numbers is closest to 7?
Sphinxa [80]

Answer:

B. √50

Step-by-step explanation:

7^{2} is 49 so √49 is 7

So,

since the <u>closest number to 49 is 50</u>, that is the answer.

7 0
3 years ago
Please Help!!!..............................
Karo-lina-s [1.5K]

Answer:

The first choice.

Step-by-step explanation:

Your graph should look like one below.

5 0
3 years ago
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
Will mark BRAINLIEST if you help
nlexa [21]
The first box is -7 and the other one is just 7
7 0
3 years ago
Read 2 more answers
Priscilla decides to order a delivery from the local sandwich shop. her order comes to $12.74 and there is a $2.30 delivery char
Tema [17]
The total is $15.04 because you must add 12.74 + 2.30
5 0
3 years ago
Read 2 more answers
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