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kogti [31]
2 years ago
7

MAY SOMEONE HELP ME PLZ 8:&:$37,$:&,$

Mathematics
1 answer:
Fed [463]2 years ago
6 0

Answer:

5. y = (x^2) / 2

6. y = -2x^2

You might be interested in
Which sequence shows a pattern where each term is 1.5 times the previous term?
Anna11 [10]

Answer:

-200, -300, -450, -675

Step-by-step explanation:

Let's look at each sequence individually, and see what relates them.

For the first sequence, -4 can be multiplied by -3/2 to get 6. Therefore, each term in the first sequence is -3/2 times the previous term. This is not what we are looking for.

For the second sequence, (n)*5 is added for the nth term after 10.

i.e. (1*5)+10=15, (2*5)+15=25, (3*5)+25=40, and so on...

This is still not the correct answer.

For the third sequence, 1.5 is added to the previous term to get the next term. This is still not what we are looking for.

Finally, let's look at the fourth sequence. -200 can be multiplied by 1.5 to get the next term, -300, which can be multiplied by 1.5 to get the following term, -450. Since each term in this sequence is multiplied by 1.5 to get the following term, (-200, -300, -450, -675...) is the sequence we're looking for.

Hope this helps!

3 0
2 years ago
Read 2 more answers
Solve for f please :)
kkurt [141]
The answer is A) i think

6 0
3 years ago
Pls help me I will give out points
marissa [1.9K]

Answer:

A, the first one

Step-by-step explanation:

On the left side, the graph is going closer to 0, that explains the first coordinate 0. On the right side, the graph approaches positive infinity, so that explains the infinity. I hope this helps!

3 0
3 years ago
5 ( x + 3 - 5x)<br> PLZ WHAT IS THIS IN SIMPLEIST FORM WILL GIVE BRAINLIEST
Tresset [83]

Answer:

-20x + 15

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP! BRAINLIEST!<br> Is this a function???<br> {(0,2),(1,4),(2,8),(3,16),(4,32),(5,64)}
Svetradugi [14.3K]

Answer:

yes

Step-by-step explanation:

it passes the verticle line test

the x-values only goto one y-value

4 0
3 years ago
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