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2 years ago

NO LINKS OR ASSESSMENT!!!Part 6: Write a rule to describe each transformation.

Mathematics

1 answer:

Scrat [10]2 years ago

6 0

Answer:

(x, y) → (x, y - 3)

Step-by-step explanation:

We observe a vertical shift.

The shift is negative by 3 units.

The rule for this translation is:

(x, y) → (x, y - 3)

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y′′ −y = 0, x0 = 0 Seek power series solutions of the given differential equation about the given point x 0; find the recurrence

sukhopar [10]

Let

$\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots$

Differentiating twice gives

$\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots$

$\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n$

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

$\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0$

$\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0$

Then the coefficients in the power series solution are governed by the recurrence relation,

$\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}$

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

$k=0 \implies n=0 \implies a_0 = a_0$

$k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}$

$k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}$

$k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}$

It should be easy enough to see that

$a_{n=2k} = \dfrac{a_0}{(2k)!}$

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

$k = 0 \implies n=1 \implies a_1 = a_1$

$k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}$

$k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}$

$k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}$

so that

$a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}$

So, the overall series solution is

$\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)$

$\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}$

4 0

2 years ago

Which system is equivalent to

sammy [17]

Answer:

D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11

Step-by-step explanation:

We are given the following two expressions:

$3x^2-4y^2=25$

and

$-6x^2-2y^2=11$

Now if we look at the option D) $6x^2 - 8y^2 = 50
$ and $-6x^2 - 2y^2 = 11$ , we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.

$6x^2 - 8y^2 = 50\\\\2(3x^2-4y^2) = 50\\\\3x^2-4y^2 = \frac{50}{2} \\\\3x^2-4y^2=25$

and the later part $-6x^2 - 2y^2 = 11$ is already the same.

Therefore, the correct answer option is D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11.

6 0

3 years ago

Read 2 more answers

Find x. Then find the measure of angles A, B and C.

mafiozo [28]

Answer:

x= 11

A=59

B= 37

C = 84

Step-by-step explanation:

A triangle adds up to 180 °.

So the equation will be a °+ b° + c° = 180°

Next, you combine like terms.

$6x + 3x + 9x+4-15-7 = 180\\18x-18=180$

Then inverse operation,

$18x-18=180\\18x=198\\x=11$

After to get a, b, and c you just need to plug in x.

$6(11)-7=a\\3(11)+4 = b\\9(11)-15=c$

4 0

3 years ago

I need help with this problem.

MariettaO [177]

Answer:

the numbers next to a variable is a coefficient, for instance in 2x 2 would be the coefficient.

the constants are the numbers without variables next to them, just numbers

like terms are the term that are similar like 2x and 8x or even 5 and 3

lm not exactly sure what they mean when asking for constant terms.

4 0

2 years ago

Work out the length of X.

vlabodo [156]

Answer:

By Pythagoras theorem

H^2=P^2+B^2

25^2=x^2+24^2

625=x^2 + 576

625-576=x^2

49=x^2

x^2=49

x=√49

x=7cm

Hope this helps uhh

6 0

2 years ago

NO LINKS OR ASSESSMENT!!!Part 6: Write a rule to describe each transformation.​

NO LINKS OR ASSESSMENT!!!Part 6: Write a rule to describe each transformation.