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shutvik [7]
2 years ago
6

NO LINKS OR ASSESSMENT!!!Part 6: Write a rule to describe each transformation.​

Mathematics
1 answer:
Scrat [10]2 years ago
6 0

Answer:

  • (x, y) → (x, y - 3)

Step-by-step explanation:

We observe a vertical shift.

The shift is negative by 3 units.

<u>The rule for this translation is:</u>

  • (x, y) → (x, y - 3)
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Based on past experience, the main printer in a university computer centre is operating properly 90% of the time. Suppose inspec
yaroslaw [1]

Answer:

a) 38.74% probability that the main printer is operating properly for exactly 9 inspections.

b) Approximately 100% probability that the main printer is operating properly for at least 3 inspections.

c) The expected number of inspections in which the main printer is operating properly is 9.

Step-by-step explanation:

For each inspection, there are only two possible outcomes. Either it is operating correctly, or it is not. The probability of the printer operating correctly for an inspection is independent of any other inspection, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Based on past experience, the main printer in a university computer centre is operating properly 90% of the time.

This means that p = 0.9

Suppose inspections are made at 10 randomly selected times.

This means that n = 10

A) What is the probability that the main printer is operating properly for exactly 9 inspections.

This is P(X = 9). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874

38.74% probability that the main printer is operating properly for exactly 9 inspections.

B) What is the probability that the main printer is operating properly for at least 3 inspections?

This is:

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.9)^{0}.(0.1)^{10} \approx 0

P(X = 1) = C_{10,1}.(0.9)^{1}.(0.1)^{9} \approx 0

P(X = 2) = C_{10,2}.(0.9)^{2}.(0.1)^{8} \approx 0

Thus:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0 + 0 = 0

Then:

P(X \geq 3) = 1 - P(X < 3) = 1 - 0 = 1

Approximately 100% probability that the main printer is operating properly for at least 3 inspections.

C) What is the expected number of inspections in which the main printer is operating properly?

The expected value for the binomial distribution is given by:

E(X) = np

In this question:

E(X) = 10(0.9) = 9

3 0
2 years ago
Use the models above to explain why a 5×2/3 equals 10×1/3
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Answer:

I kind of need the models to help with this one

4 0
2 years ago
PLSSS HELP IF YOU TURLY KNOW THISS
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Answer:

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John bought 4 pants that each cost the same amount and a pair of sneakers that cost $65. The items he bought cost a total of $14
Rzqust [24]

Answer:p=$20

Step-by-step explanation:

145-65=80

80/4=20

so each pant costs $20

p=$20

7 0
2 years ago
Can someone please help
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Answer:

(6, -4)

Step-by-step explanation:

If ABCD is dilated by a factor of 2, you multiply the coordinates by 2. For the coordinate D', you would multiply 3 by 2 to get 6 and you would multiply -2 by 2 to get -4. Answer: (6, -4)

3 0
3 years ago
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