It took 500 newtons of force to push a car 4 meters. How much work was done?
1 answer:
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Answer:
Explanation:
From the question we are told that
Distance b/e antenna's
Frequency of antenna Radiation
Distance from receiver
Intensity of Receiver
Distance difference of the receiver b/w antenna's
Generally the equation for Phase difference is mathematically given by
Therefore phase difference f between the two radio waves produced by this path difference is given as
The elastic potential energy (Ep) is given by 
Data:
Ep = ? (Joule)
k = 20 N/m
x (displacement) = 0.20 m
Solving:
Data:
Ep = ? (Joule)
k = 20 N/m
x (displacement) = 0.20 m
Solving:
Answer:
a) fem = - 2.1514 10⁻⁴ V, b) I = - 64.0 10⁻³ A, c) P = 1.38 10⁻⁶ W
Explanation:
This exercise is about Faraday's law
fem =
where the magnetic flux is
Ф = B x A
the bold are vectors
A = π r²
we assume that the angle between the magnetic field and the normal to the area is zero
fem = - B π 2r dr/dt = - 2π B r v
linear and angular velocity are related
v = w r
w = 2π f
v = 2π f r
we substitute
fem = - 2π B r (2π f r)
fem = -4π² B f r²
For the magnetic field of Jupiter we use the equatorial field B = 428 10⁻⁶T
we reduce the magnitudes to the SI system
f = 2 rev / s (2π rad / 1 rev) = 4π Hz
we calculate
fem = - 4π² 428 10⁻⁶ 4π 0.10²
fem = - 16π³ 428 10⁻⁶ 0.010
fem = - 2.1514 10⁻⁴ V
for the current let's use Ohm's law
V = I R
I = V / R
I = -2.1514 10⁻⁴ / 0.00336
I = - 64.0 10⁻³ A
Electric power is
P = V I
P = 2.1514 10⁻⁴ 64.0 10⁻³
P = 1.38 10⁻⁶ W