It took 500 newtons of force to push a car 4 meters. How much work was done?
1 answer:
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Answer:
245.45km in a direction 21.45° west of north from city A
Explanation:
Let's place the origin of a coordinate system at city A.
The final position of the airplane is given by:
rf = ra + rb + rc where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:
rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km
rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km
The module of this position is:
And the angle measure from the y-axis is:
So the answer is 245.45km in a direction 21.45° west of north from city A
Answer:
The electric flux is
Explanation:
Given:
- Radius of the disc R=0.50 m
- Angle made by disk with the horizontal
- Magnitude of the electric Field
The flux of the Electric Field E due to the are dA in space can be found out by using Gauss Law which is as follows
where
is the total Electric Flux
- E is the Electric Field
- dA is the Area through which the electric flux is to be calculated.
Now according to question we have
Hence the electric flux is calculated.