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bija089 [108]
3 years ago
10

how fast will and in what direction will a 20kg object accelerate if one force pushes at a 30 degree angle and another pushes at

a 120 degree angle? these angles are principal angles.​
Physics
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

|a|=2.83\ m/s^2

\theta=75^o

Explanation:

<u>Net Force And Acceleration </u>

The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by

\vec F_n=m\vec a

The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N

The components of the first force are

\vec F_1=

\vec F_1=\ N

The components of the second force are

\vec F_2=

\vec F_2=\ N

The net force is

\vec F_n=

\vec F_n=\ N

The magnitude of the net force is

|F_n|=\sqrt{14.64^2+54.64^2}

|F_n|=\sqrt{3200}=56.57\ N

The acceleration has a magnitude of

\displaystyle |a|=\frac{|F_n|}{m}

\displaystyle |a|=\frac{56.57}{20}

|a|=2.83\ m/s^2

The direction of the acceleration is the same as the net force:

\displaystyle tan\theta=\frac{54.64}{14.64}

\theta=75^o

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ahrayia [7]

Answer:

I know the first one is C.) 4J. I don't know of the answer for the second oneis suppose to be in N/m form? but I got

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3 years ago
What is the velocity of a ball dropped from a height of 150 m when it hits the ground? Take the upward direction as positive.
djyliett [7]

Answer:

The velocity of the ball when its hit the ground will be 54.22 m/sec    

Explanation:

We have given height from which ball is dropped h = 150 m

Acceleration due to gravity g=9.8m/sec^2

As the ball is dropped so initial velocity will be zero so u = 0 m/sec

According to third equation of motion we know that v^2=u^2+2gh

v^2=0^2+2\times 9.8\times 150

v=54.22m/sec

So the velocity of the ball when its hit the ground will be 54.22 m/sec

7 0
3 years ago
Two parallel wires are separated by 5.60 cm, each carrying 2.65 A of current in the same direction. (a) What is the magnitude of
ololo11 [35]

Explanation:

It is given that,

The separation between two parallel wires, r = 5.6 cm = 0.056 m

Current in both the wires is 2.65 A

(a) We need to find the magnitude of the force per unit length between the wires. It can be given by :

\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi r}\\\\\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.65\times 2.65}{2\pi \times 0.056}\\\\\dfrac{F}{l}=2.5\times 10^{-5}\ N/m

(b) As the current is in same direction, the wires will attract each other.

5 0
3 years ago
A vertical straight wire 35.0 cmcm in length carries a current. You do not know either the magnitude of the current or whether t
12345 [234]

Answer:

1.714\ \text{A}

Explanation:

F = Magnetic force = 0.018 N

B = Magnetic field = 0.03 T

L = Length of wire = 35 cm

\theta  = Angle between current and magnetic field = 90^{\circ}

Magnetic force is given by

F=IBL\sin\theta\\\Rightarrow I=\dfrac{F}{BL\sin\theta}\\\Rightarrow I=\dfrac{0.018}{0.03\times 35\times 10^{-2}\times \sin90^{\circ}}\\\Rightarrow I=1.714\ \text{A}

The magnitude of the current is 1.714\ \text{A}.

8 0
3 years ago
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