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Afina-wow [57]
3 years ago
12

THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THAN

KS!!! What is the fundamental frequency of a mandolin string that is 42.0 cm long when the speed of waves of the string is 329 m/s? with working outs
Physics
2 answers:
Iteru [2.4K]3 years ago
7 0

Explanation:

이것이 정답입니다!!! (this is the correct answer)

#폴로 (주)따라 (follow me)

#이 대답을 마음(heart this answer)

Karo-lina-s [1.5K]3 years ago
6 0

Answer:

450km because this night founder

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Help please i don’t know
Fantom [35]

Answer:

Explanation:

Potential energy at the top of the slide

PE = mgh = 49(9.8)(3) = 1,440.6 J

Energy converted to work of friction

W = Fd = 35(10) = 350 J

Converted potential that becomes kinetic energy

1440.6 - 350 = 1090.6 J

KE = ½mv²

v = \sqrt{2KE/m}

v = \sqrt{2(1090.6)/49}

v = 6.671902...

v = 6.7 m/s

4 0
2 years ago
A charge −1.3 × 10−5 C is fixed on the x-axis at 7 m, and a charge 1 × 10−5 C is fixed on the y-axis at 4 m. Calculate the magni
wariber [46]

Answer:

6104 N/C.

Explanation:

Given:

k = 8.99 × 10^9 Nm2/C^2

Qx = 1.3 × 10^-5 C

rx = 7 m

Qy = 1 × 10−5 C

ry = 4 m

E = F/Q

= kQ/r^2

Ex = (8.99 × 10^9 × 1.3 × 10^−5) ÷ 7^2

= 2385.1 N/C.

Ey = (8.99 × 10^9 × 1.0 × 10^−5) ÷ 4^2

= 5618.75 N/C

Eo = sqrt(Ex^2 + Ey^2)

= sqrt(3.157 × 10^7 + 5.69 × 10^6)

= 6104 N/C.

5 0
3 years ago
Need help on this one please
mamaluj [8]
The atomic number is a neutron
3 0
3 years ago
Is my answer correct or no?
irinina [24]
 No your answer is incorrect. Would you like the correct one?
8 0
4 years ago
Read 2 more answers
In his experiments on "cathode rays" during which he discovered the electron, J.J. Thomson showed that the same beam deflections
Andrews [41]

Answer:

A) his observation is of little importance ,

B) This observation is very important since the movement of the point of light depends on the relationship between the already magnetic electric force

C)   see that in this second case it is 4 times less  

D) the force of gravity is of the order of 10⁻⁴⁰

therefore it is 10²⁸ times less than the electric force,

Explanation:

A) This observation is of little importance since the cacodylate ray tube always emits electrons, regardless of the material of which it is made.

B) This observation is very important since the movement of the point of light depends on the relationship between the already magnetic electric force

C) the elect's load is 1.6 10⁻¹⁹ C its mass is 9.1 10⁻³¹ kg, let's look for its relation

        e / m = 1.6 10⁻¹⁹ / 9.1 10⁻³¹

         e / m = 0.1 758 10 10¹² N

look for this in the case of an atom, let's use the lightest atom hydrogen

the homogenize have an electron of charge 1.6 10⁻¹⁹ C

and a mass of 1.6735575 10⁻²⁷ ka

        e / M = 1.6 10⁻⁻¹⁹ / 1.67 10⁻²⁷

       e / M = 0.96 10⁸ N

We see that in this second case it is 4 times less

D) the force of gravity is of the order of 10⁻⁴⁰

therefore it is 10²⁸ times less than the electric force, therefore it should not contribute to the movement of the light beam

8 0
3 years ago
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