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Afina-wow [57]
3 years ago
12

THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THAN

KS!!! What is the fundamental frequency of a mandolin string that is 42.0 cm long when the speed of waves of the string is 329 m/s? with working outs
Physics
2 answers:
Iteru [2.4K]3 years ago
7 0

Explanation:

이것이 정답입니다!!! (this is the correct answer)

#폴로 (주)따라 (follow me)

#이 대답을 마음(heart this answer)

Karo-lina-s [1.5K]3 years ago
6 0

Answer:

450km because this night founder

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Help ASAP!<br> Everything on screenshot
BARSIC [14]

Answer:

For the first one, its B) cities B and C

I'm not so sure, but I hope this helps.

7 0
3 years ago
car was moving in a straight road of length 320 km it covered 240 km with an average velocity 75 km/hr then it ran out of fuel a
Stella [2.4K]

The average velocity of the car for the whole journey is 69.57 km/h.

The given parameters:

  • <em>Length of the road, L = 320 km</em>
  • <em>Distance covered = 240 km at 75 km/h</em>
  • <em>time spent refueling, t₂ = 0.6 hr</em>
  • <em>Final velocity, = 100 km/hr</em>

The time spent by the before refueling is calculated as follows;

t = \frac{d}{v} \\\\t_1 = \frac{240}{75} \\\\t_1 = 3.2 \ hours

The time spent by the car for the remaining journey;

t_3 = \frac{320 - 240}{100} \\\\t_3 = 0.8 \ hr

The total time of the journey is calculated as follows;

t = t_1 + t_2 + t_3\\\\t = 3.2 \ hr \ + \ 0.6 \ hr \ + \ 0.8 \ hr\\\\t = 4.6 \ hours

The average velocity of the car for the whole journey is calculated as follows;

v = \frac{total \ distance }{total \ time} \\\\v = \frac{320}{4.6} \\\\v = 69.57 \ km/h

Learn more about average velocity here: brainly.com/question/6504879

6 0
2 years ago
.
WARRIOR [948]

Answer:

Explanation:distance-time =speed

a,V =s/t

V=2m/2s

V=1m/s

b,v=s/t

V=80m/40s

V= 2m/s

The average speed is 2m/s

8 0
2 years ago
Find the volume of a sphere of radius 10 mm.
vredina [299]

Answer:

Explanation: This is done using the equation:

\frac{4}{3} π R^{3}

Because the Radius is a know value. We have the following.

\frac{4}{3} π (10mm)^{3}

Which is:

4188.7902 mm

5 0
3 years ago
A transmission diffraction grating with 420 lines/mm is used to study the light intensity of di event orders (n). A screen is lo
Goshia [24]

Answer:

Explanation:

Diffraction grating is used to form interference pattern of dark and bright band.

Distance between adjacent slits (a ) = 1 / 420 mm

= 2.38 x 10⁻³ mm

2.38 x 10⁻⁶ m

wave length of red light

= 680 x 10⁻⁹ m

For bright red band

position x on the screen

= n λD / a ,         n = 0,1,2,3 etc

D = distance of screen

putting n = 1 , 2 and 3 , we can get three locations of bright red band.

x₁ = λD / a

=  680 x 10⁻⁹ x 2.8 / 2.38 x 10⁻⁶

= .8 m

= 80 cm

Position of second bright band

= 2 λD / a

= 2 x 80

= 160 cm

Position of third bright band

= 3 λD / a

= 3 x 80

= 240 cm

5 0
3 years ago
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