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jenyasd209 [6]
3 years ago
7

When water evaporates, what happens to its molecules?

Chemistry
1 answer:
Scrat [10]3 years ago
7 0
It’s the first one: A. the water molecules stay the same they just change phase to a gas
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I need help asap please :) it says to “identify the reactants.”
Lelechka [254]

The reactants are A: Carbon Dioxide and water

5 0
3 years ago
Grams smallest to kilograms and milligrams
Anna007 [38]
Grams is smaller than kilograms but larger than milligrams

1g = 0.001 kg
1g = 1000 mg

Grams is an SI unit for mass.

International System of Units (SI Units) are organized body of measurements for physical quantity. They are set to be the norm or global norm scaling for every physical quantity which includes kilogram, meter, second, ampere, kelvin, candela and mole. These measurements then can increase or decrease by the power of ten, multiplied or divided. As said and explained, the SI is helpful in describing objects because 
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2.       </span>SI Units are a global set of measurement hence, we can communicate with ease from western to eastern countries with these measurements without having problems in terms of portraying or displaying a set of physical quantities.</span><span> </span>

4 0
3 years ago
How can the atomic number and mass number be used to determine the amount of each subatomic particle present in an atom of a giv
Goshia [24]
Because of the environment that
4 0
4 years ago
A maple tree could be studied in many fields of science. What aspect of a maple tree might be studied in chemistry
Elden [556K]

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botany because a maple tree is a plant

Explanation:

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4 years ago
2 C6H14 + 19 O2 --&gt; 12 CO2 + 14 H2O
Rashid [163]

Answer:

4.06 mol H₂O

Explanation:

  • 2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

First we <em>convert the given masses of reactants into moles</em>, using <em>their respective molar masses</em>:

  • 250 g O₂ ÷ 32 g/mol = 7.81 mol O₂
  • 50 g C₆H₁₄ ÷ 86 g/mol = 0.58 mol C₆H₁₄

Now we <u>calculate how many O₂ moles would react completely with 0.58 C₆H₁₄ moles</u>, using the <em>stoichiometric coefficients of the reaction</em>:

  • 0.58 mol C₆H₁₄ * \frac{19molO_2}{2molC_6H_{14}} = 5.51 mol O₂

As there are more O₂ moles than required (7.81 vs 5.51), O₂ is the reactant in excess. That means that <em>C₆H₁₄ is the limiting reactant</em>.

Now we can <u>calculate how much water can be formed</u>, using <em>the number of moles of the limiting reactant</em>:

  • 0.58 mol C₆H₁₄ * \frac{14molH_2O}{2molC_6H_{14}} = 4.06 mol H₂O
5 0
3 years ago
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