Explanation:
According to the Henderson-Hasselbalch equation,
pH =
+ ![\frac{log[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7Blog%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
Given values are pH = 6,
= 8
Putting given values into the above equation as follows.
6 = 8 + ![\frac{log [A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7Blog%20%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
= -2
= antilog -2
= 0.01
But according to the question, we need protonated to deprotonated ratio of ![\frac{[HA]}{[A^{-}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHA%5D%7D%7B%5BA%5E%7B-%7D%5D%7D)
= 
= 100
Thus, we can conclude that ratio of the protonated to the deprotonated form of the acid is
.
The equation is already balanced
2AgNO3 + MgCl2 => 2AgCl + Mg(NO3)2
The answer is c because ice is cold
Answer:
large supply of nutrients.
Explanation:
In a wetland, the soil is covered by water or is almost covered by water. This water may be coming upwards from an underground aquifer. Wetlands are covered by water for most of the year.
They are sheltered waters and do provide habitats for many living things.
Nutrients such as; Carbon sulfur, phosphorus, carbon, and nitrogen are cycled within the soil of wetlands hence wetlands have a large supply of nutrients.
Answer:

Explanation:
Hello there!
In this case, since the reaction for the formation of ammonia is:

We can evidence the 1:2 mole ratio of nitrogen gas to ammonia; therefore, the appropriate stoichiometric setup for the calculation of the moles of the latter turns out to be:

And the result is:

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