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GalinKa [24]
4 years ago
6

Describe how fuel oil can be changed into gasoline?

Chemistry
1 answer:
Pavlova-9 [17]4 years ago
4 0
By fractional distalation which is heating something up so it boils and evaporate then the gas condenses and runs down the tube for petrol.
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True or false In the periodic table, the atomic number is found above the chemical symbol.
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Answer:

In the periodic table, the atomic number is found above the chemical symbolb is true.

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Disccuss what happens to copper in photochromic lenses from a redox perspective.
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The simplest ion that copper forms in solution is the typical blue hexaaquacopper(II) ion - [Cu(H2O)6]<span>2+</span>
8 0
3 years ago
Help! please! hurry! I will mark brainliest if you get it correct!! NO SPAM!!!!!!
Troyanec [42]

Answer: 5.747 * 10^14 Hz

Explanation:

Convert 522nm to m = 522 * 10^-9 m (since 1nm=10^-9m)

If c = wavelength * frequency, where c is the speed of light (3.0 * 10^8 m/s), then you can manipulate the equation to solve for frequency (f).

f = c / wavelength

Plug in the given numbers:

f = (3.0 * 10^8) / (10^-9)

f = 5.747 * 10^14 Hz

4 0
3 years ago
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Calculate the maximum numbers of moles and grams of iodic acid (HIO₃) that can form when 635 g of iodine trichloride reacts with
poizon [28]

What is Chemical Reaction?

A chemical reaction occurs when a certain group of molecules converts into another form without affecting their nuclei; only the transfer or sharing of electrons and the building and breaking of bonds occur.

Main Content

Known :

\mathrm{ICl}_{3}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{ICl}+\mathrm{HIO}_{3}+\mathrm{HCl}

Mass of ICI_3 = 635g

Mass of H_2O = 118.5g

Calculations :

First, balance the given chemical equation by place 2,3 and 5 as the coefficients of ICI_3, H_2O and HCl,\\ Respectively

2 \mathrm{ICl}_{3}+3 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{ICl}+\mathrm{HIO}_{3}+5 \mathrm{HCl}

We multiply the given mass of ICl_3 by the reciprocal of its molar mass to get the number of moles. The molar mass of ICl_3 is 233.26g/mol

\text { Moles of } \mathrm{ICl}_{3}=635 \mathrm{~g} \mathrm{ICl}_{3} \times \frac{1 \mathrm{~mol} \mathrm{ICl}_{3}}{233.26 \mathrm{~g} \mathrm{ICl}_{3}}=2.7223 \mathrm{~mol}  \mathrm{ICl}_{3}

Them, we multiply the ratio between ICl_3 and HIO_3. based on the chemical equation, the molar ratio 1 mol HIO_3/2  mol ICl_3.

\text { Moles of } \mathrm{HIO}_{3} \text { formed }=2.7223 \mathrm{~mol} \mathrm{ICl}_{3} \times \frac{1 \mathrm{~mol} \mathrm{HIO}_{3}}{2 \mathrm{~mol} \mathrm{ICl}_{3}}=1.3612 \mathrm{~mol} \mathrm{HIO}_{3}

For water, we again multiply the given mass H_2O by the reciprocal of its molar mass to get the number if moles. The molar mass of H_2O is 18.02g/mol

\text { Moles of } \mathrm{H}_{2} \mathrm{O}=118.5 \mathrm{~g} \mathrm{H}_{2} \mathrm{O} \times \frac{1 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}{18.02 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}}=6.5760 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}

Then, we multiply the molar ratio between H2O and HIOs. Based on the chemical equation, the molar ratio is 1 mol HIO_3/3 Mole H_2O

\text { Moles of } \mathrm{HIO}_{3} \text { formed }=6.5760 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O} \times \frac{1 \mathrm{~mol} \mathrm{HIO}_{3}}{3 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}=2.1920 \mathrm{~mol} \mathrm{HIO}_{3}

We can see that the limiting reactant is ICL_3 since the given mass of ICl_3 forms lesser product than water does. Thus , the maximum number of moles of HIO_3 formed is 1.36 mol HIO_3. We now multiply the molar mas of HIO_3 to the calculated number of moles. The molar mass of HIO_3 is 175.91 g/mol.

Mass of HIO_3 formed (Max) =1.3612 \mathrm{~mol} \mathrm{HIO}_{3} \times \frac{175.91 \mathrm{~g} \mathrm{HIO}_{3}}{1 \mathrm{~mol} \mathrm{HIO}}=239 \mathrm{~g} \mathrm{HIO}_{3}

We multiply the number of moles of ICl_3 by the molar ratio between ICl_3 and H_2O which is 3 mol H_2O mol ICl_3 we get the number of moles of H_2O reacted. Then, we multiply the molar mass of water.

Mass of H_2O reacted =2.7223 \mathrm{~mol} \mathrm{ICl} 3 \times \frac{3 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}{2 \mathrm{~mol} \mathrm{ICl}_{3}} \times \frac{18.02 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}

Mass of H_2O reacted = 73.6g H_2O

We subtract the mass of H_2O reacted from the given mass of H_2O.

Mass of H_2O = 118.5 - 73.6g = 44.9g H_2O

To learn more about Chemical Reaction

brainly.com/question/11231920

#SPJ4

3 0
2 years ago
What functional group is found in an alcohol?
Contact [7]

Answer:

an alcohol is a Hydroxyl group due to the OH~ that is associated with it's molecules

5 0
3 years ago
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