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3 years ago

3. The honeycomb-like appearance of this sandstone is a result of.

Physics

2 answers:

sladkih [1.3K]3 years ago

6 0

Answer:

The answer is "Option C".

Explanation:

Wedging Freeze is generated by repeated freezing. Freeze wedging occurs, whenever the water is turned into ice as a result of the 9 percent expansion. When it freezes, cracks full of water are forced to separate further. and other options are incorrect, that can be described as follows:

In option A, It is a state where the element converts into a liquid, that's why it is not correct.
In option B, It is a reaction in which the bonds of water is divided into particular substance, that's why it is not correct.
In option D, It is a form of mechanical or physical rock weathering, that's it is not correct.

LenaWriter [7]3 years ago

4 0

Answer

C. frost wedging.

Explanation:

The honey-comb-like structure formed on the sand stone is the result of stresses due to frost wedging in the sandstone.

As we know that the microscopic structure of snow is hexagonal and similar is the pattern being discussed here for a honeycomb.

Frost wedging is the process of wearing of rocks by the repeated cycles of freezing and melting of water in the porous cavities of the sandstone.

Due to anomalous expansion of water on freezing it exerts stress on the inner surfaces of the space it occupies in the porosity.

As we know that the structure of the molecular bonds is arranged in a cage-like structure of ice which wears out the particles of the rock leaving a honeycomb structured impression due to the stresses.

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Pls help on this one

lidiya [134]

Answer:

Explanation:

because 50.0/10.0 = 5.0

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3 years ago

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A sealed container holding 0.0255 L of an ideal gas at 0.981 atm and 65 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w

user100 [1]

Answer:

0.911 atm

Explanation:

In this problem, there is no change in volume of the gas, since the container is sealed.

Therefore, we can apply Gay-Lussac's law, which states that:

"For a fixed mass of an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"

Mathematically:

$p\propto T$

where

p is the gas pressure

T is the absolute temperature

For a gas undergoing a transformation, the law can be rewritten as:

$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

where in this problem:

$p_1=0.981 atm$ is the initial pressure of the gas

$T_1=65^{\circ}+273=338 K$ is the initial absolute temperature of the gas

$T_2=41^{\circ}+273=314 K$ is the final temperature of the gas

Solving for p2, we find the final pressure of the gas:

$p_2=\frac{p_1 T_2}{T_1}=\frac{(0.981)(314)}{338}=0.911 atm$

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4 years ago

What is the average velocity of a car that travels 30 kilometers due wet in 0.50

rodikova [14]

Answer:

60km/hr west

Explanation:

When you are dealing with velocity you always name the direction its going in

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4 years ago

In the doorknob shown above, when the handle is rotated a distance of 189 millimeters, the spindle is rotated a distance of 27 m

Alisiya [41]

If my math is right its A) 7

because 189 divided by 27 is 7

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3 years ago

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what do you mean by momentum? avehicle is runing with a velocity of 5m/s. it the momentum of the vehicle is 5000kg m/s. what is

Fantom [35]

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3 years ago