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VMariaS [17]
3 years ago
8

Mike rides his horse with a constant speed of 20 km/h. How far can he travel in 4 hours?

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer:

Mike can travel 80 Km in 4 hours

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A futuristic train rushes past you at an incredible, relativistic speed such that it appears to only be 80% as long as you know
Fed [463]

Answer:

v = 0.6c = 1.8 x 10⁸ m/s

Explanation:

From Einstein's theory of relativity, we know that the length of an object contracts while traveling at a speed relative to speed of light. The contraction is according to following equation:

L = L_{0}\sqrt{1 - \frac{v^2}{c^2}}

where,

L = Relative Length

L₀ = Rest Length

According to given:

L = 0.8 L₀

c = speed of light = 3 x 10⁸ m/s

v = relative speed of train = ?

Therefore,

0.8L_{0} = L_{0}\sqrt{1 - \frac{v^2}{c^2} } \\\\0.8 = \sqrt{1 - \frac{v^2}{c^2} }

squaring on both sides:

0.64 = 1-\frac{v^2}{c^2}\\\\\frac{v^2}{c^2} = 1-0.64 \\v^2= 0.36c^2\\

taking square root on both sides:

<u>v = 0.6c = 1.8 x 10⁸ m/s</u>

3 0
3 years ago
What is a phone message?
malfutka [58]
A message telephone messagemessage  a communication usually brie that is written or spoken or signaled; "hesent a three-word <span>message"</span>
8 0
3 years ago
Read 2 more answers
1 poir
djverab [1.8K]

Answer:

D) 735 J(oules)

Explanation:

Work is defined as force * distance

Force is defined as mass * acceleration

Given a mass of 15 kg and a gravitational acceleration of 9.8 m/s² since the box is being lifted up, the force being applied to the box is 15 kg * 9.8 m/s² = 147 N

Since the distance is 5 meters, the work done is 147 N * 5 m = 735 N/m = 735 J, making D the correct answer.

4 0
3 years ago
Do you think distance and time are relevant terms in describing motion?
olya-2409 [2.1K]

Answer:

yes

Explanation:

because motion is relevant

6 0
3 years ago
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Earning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
lana [24]

Answer:

the work done by the 30N force is 4156.92 J.

For this problem, they don´t ask you to determine the work of the total force applied in the block. They only want the work done for the force of 30N, with an angle of 30º respectively of the displacement and a traveled distance of 160m. So:

W=F·s·cos(α)=30N·160m·cos(30º)=4156.92J

8 0
3 years ago
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