Answer:
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<h2>
Tension in ropes are 333.33 N and 566.67 N.</h2>
Explanation:
Refer the given figure showing the arrangement.
For having stability we have torque at A and B are zero.
Sum of Torques at A = 0
700 x 1 + 200 x 1.5 - Q x 3 = 0
3Q = 1000
Q = 333.33 N
Sum of Torques at B = 0
200 x 1.5 + 700 x 2 - P x 3 = 0
3P = 1700
P = 566.67 N
Tension in ropes are 333.33 N and 566.67 N.
M = 150 kg.
Final velocity, v = 14 m/s
Initial Velocity, u = 6 m/s
Impulse = <span> m(v - u)</span>
= 150*(14 - 6)
= 150*8 = 1200 kgm/s or 1200 Ns<span> </span>
Answer:position relative to the starting point
Explanation: