Mike rides his horse with a constant speed of 20 km/h. How far can he travel in 4 hours?

It is known that the 10 kg pipe will roll up the ramp and not slide on the ramp when P becomes sufficiently large. Using the rol

riadik2000 [5.3K]

Answer:

65.73N

Explanation:

The frictional force is a force that opposes the motion of an object on a flat surface or an inclined surface.

It is always acting up an incline plane .

Since the pipe will tend to roll up the plane, then both the impending force P also known as frictional force and the moving force Fm both will be acting up the plane.

The net force acting up the plane is

Fnet = P + Fm... (1)

The force perpendicular to the plane known as the normal reaction R must be equal to the force acting along the ramp in other to keep the body in equilibrium i.e R = Fnet

If R = W = mgcos (theta)

and Fm = mgsin(theta)

Then mgcos theta = Fnet

mgcos (theta) = P+Fm

mgcos (theta) = P+mgsin(theta)

P = mgcos (theta) - mgsin(theta)... (2)

Given mass = 10kg

g = 9.81m/s

We can get theta from the formula;

µ = Ff/R = wsin theta/wcos theta

µ = sin theta/cos theta

µ = tan(theta)

0.3 = tan (theta)

theta = arctan0.3

theta = 16.7°

P = 10(9.81)cos16.7° - 10(9.81)sin16.7°

P = 98.1(cos16.7°-sin16.7°)

P = 98.1(0.67)

P = 65.73N

The minimum force P required to cause impending motion is 65.73N

5 0

3 years ago

If the earth's magnetic field has strength 0.50 gauss and makes an angle of 20.0 degrees with the garage floor, calculate the ch

lys-0071 [83]

Answer:

ΔΦ = -3.39*10^-6

Explanation:

Given:-

- The given magnetic field strength B = 0.50 gauss

- The angle between earth magnetic field and garage floor ∅ = 20 °

- The loop is rotated by 90 degree.

- The radius of the coil r = 19 cm

Find:

calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.

Solution:

- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.

- The strength of magnetic field B and the are of the loop A remains constant. So we have:

Φ = B*A*cos(θ)

ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )

- The initial angle θ_1 between the normal to the coil and B was:

θ_1 = 90° - ∅

θ_1 = 90° - 20° = 70°

The angle θ_2 after rotation between the normal to the coil and B was:

θ_2 = ∅

θ_2 = 20°

- Hence, the change in flux can be calculated:

ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )

ΔΦ = -3.39*10^-6

8 0

3 years ago

we had to drive 150 miles to the hotel we left at 1 p.m. and got there at 4 p.m. what is our average speed

marta [7]

The answer is 50mi/hr

4 0

3 years ago

Read 2 more answers

A gazelle leaps from a cliff 2.5 m high with a speed of 5.6m/s.

jeyben [28]

Initial speed of Gazelle is along x direction and its value will be

$v_x = 5.6 m/s$

also its initial height is given as

$y = 2.5 m$

Part a)

now from kinematics along Y direction

$\Delta y = v_y t + \frac{1}{2} at^2$

as we know that

$\Delta y = 0$

$v_y = 0$

$a = 9.8 m/s^2$

$2.5 = 0 + \frac{1}{2} (9.8) t^2$

$t = 0.714 s$

Part b)

distance moved horizontally

$\Delta x = v_x t$

as we know that

$v_x = 5.6 m/s$

now we will have

$v_x = 5.6 (0.714) = 4m$

so it will lend at distance of 4 m.

Part c)

final velocity in vertical direction

$v_{fy} = v_y + at$

$v_{fy} = 0 + (9.8)(0.714) = 7 m/s$

$v_x = 5.6 m/s$

so net speed will be

$v^2 = v_x^2 + v_y^2$

$v^2 = 7^2 + 5.6^2$

$v = 8.96 m/s$

7 0

3 years ago

Which of the following advances in food production were attributed to the Green Revolution of the 1960s and 1970s? A. use of cro

LuckyWell [14K]

I believe the correct answer from the choices listed above is the last option. The advances in food production that were attributed to the Green Revolution of the 1960s and 1970s are drought-resistant varieties of crop plants.
Hope this answers the question. Have a nice day.

5 0

3 years ago