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natta225 [31]
3 years ago
14

The magnitude of a negative of a vector is negative. O True O False

Physics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

The given statement is false.

Explanation:

For any negative vector

\overrightarrow{r}=-x\widehat{i}-y\widehat{j}

The magnitude of the vector is given by

|r|=\sqrt{(-x)^{2}+(-y)^{2}}\\\\|r|=\sqrt{x^2+y^2}

As we know that square root of any quantity cannot be negative thus we conclude that the right hand term in the above expression cannot be negative hence we conclude that magnitude of any vector cannot be negative.

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With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be
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Answer:

The resistance must be 6.67\Omega

Solution:

Resistance, R_{1} = 20\Omega

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For the current to be the same when the switch is open or closed, the resistances must be connected in parallel as current is distributed in parallel with the same voltage across the circuit:

Thus in parallel:

\frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}

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Light in air enter crown glass (n = 1.52) at an angle of 35 degrees. What is the refracted angle?
Dovator [93]

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22.17 degree

Explanation:

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