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grin007 [14]
3 years ago
12

1 Point

Chemistry
1 answer:
Mila [183]3 years ago
7 0

Answer:

Option C. 296K

Explanation:

T°C = 23°C

To covert the above to Kelvin temperature, use the following equation

T(K) = T°C + 273

T(K) = 23 + 273

T(K) = 296K

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How many molecules are in 41.8 g of sulfuric acid
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× 10²³ molecules are in 41.8 g of sulfuric acid

Explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

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Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

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\frac{0.426187053\text{ }mol}{1\text{ }mol}\times6.022×10²³\text{ }molecules=2.57\times10^{23}\text{ }molecules

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.

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