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grin007 [14]
3 years ago
12

1 Point

Chemistry
1 answer:
Mila [183]3 years ago
7 0

Answer:

Option C. 296K

Explanation:

T°C = 23°C

To covert the above to Kelvin temperature, use the following equation

T(K) = T°C + 273

T(K) = 23 + 273

T(K) = 296K

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The force of attraction between two masses of different substances that are in contact
Colt1911 [192]

Answer:

A. Cohesion

Explanation:

I hope it's help you

5 0
2 years ago
You bought a new car and estimated that your monthly payment would be $312. However, your actual payment amount was $325. How mu
Romashka-Z-Leto [24]

Answer:

The error would be $13.

Explanation:

Given data:

Actual payment = $325

estimated payment = $312

Error = ?

Solution:

Error =  Estimated payment - Actual payment

Error = $312  -  $325

Error = -$13

we can discard the negative sign and consider the absolute value. The error would be $13.

5 0
3 years ago
Rxn
givi [52]

Answer: The enthalpy of formation of SO_3 is  -396 kJ/mol

Explanation:

Calculating the enthalpy of formation of SO_3

The chemical equation for the combustion of propane follows:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(O_2(g))})]

We are given:

\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-297kJ/mol\\\Delta H^o_{rxn}=-198kJ

Putting values in above equation, we get:

-198=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta -297)+(1\times (0))]\\\\\Delta H^o_f_{(SO_3(g))}=-396kJ/mol

The enthalpy of formation of SO_3 is -396 kJ/mol

4 0
3 years ago
When a drawing of a circle made in the center of a piece of paper with a black marker gets wet, the marker bleeds, and as the wa
suter [353]

Answer:

D) Chromatography

Explanation:

8 0
3 years ago
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kakasveta [241]
The answer is 4 an atom
4 0
3 years ago
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