1 Point

Chemistry

1 answer:

Mila [183]3 years ago

7 0

Answer:

Option C. 296K

Explanation:

T°C = 23°C

To covert the above to Kelvin temperature, use the following equation

T(K) = T°C + 273

T(K) = 23 + 273

T(K) = 296K

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?A scientist is investigating how the lunar cycle affects the number of sea turtles nesting each night. Which of the following i

alexgriva [62]

Answer:

Number of nesting turtles

Explanation:

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3 years ago

What is the number of the lowest energy level that contains an f sublevel?

forsale [732]

Answer: n = 4.

Explanation:

1) The main energy level is represented by the principal (main) quantum number, n. It can be 1, 2, 3, 4, 5,6, or 7. It is the period number in the periodic table.

2) The next quantum number is the Azimuthal quantum number (ℓ), also known as angular quantum number. It indicates the subshell (sublevel) or type of orbital.

This quantun number may be:

s, p, d, or f.

3) For n = 1, there is only one ℓ number: 0; which is the orbital s

For n = 2, there are two possible ℓ numbers: 0 and 1; which are the orbitals s and p.

For n = 3, there are three possible ℓ numbers: 0, 1, and 2, which are the orbitals s, p, and d:

For n = 4, there are four possible ℓ numbers:0, 1, 2, and 3; which are the orbitals s, p, d, and f.

So, the f sublevel appears first time when n = 4, i.e the number of the lowest energy level that contains an f sublevel is 4.

5 0

3 years ago

EXTRA POINTSSS 1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?

AlekseyPX

Answer:

Concentration of OH⁻:

1.0 × 10⁻⁹ M.

Explanation:

The following equilibrium goes on in aqueous solutions:

$\text{H}_2\text{O}\;(l)\rightleftharpoons \text{H}^{+}\;(aq) + \text{OH}^{-}\;(aq)$ .

The equilibrium constant for this reaction is called the self-ionization constant of water:

$K_w = [\text{H}^{+}]\cdot[\text{OH}^{-}]$ .

Note that water isn't part of this constant.

The value of $K_w$ at 25 °C is $10^{-14}$ . How to memorize this value?

The pH of pure water at 25 °C is 7.
$[\text{H}^{+}] = 10^{-\text{pH}} = 10^{-7}\;\text{mol}\cdot\text{dm}^{-3}$
However, $[\text{OH}^{-}] = [\text{H}^{+}]=10^{-7}\;\text{mol}\cdot\text{dm}^{-3}$ for pure water.
As a result, $K_w = [\text{H}^{+}] \cdot[\text{OH}^{-}] = (10^{-7})^{2} = 10^{-14}$ at 25 °C.