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3 years ago

Write the electron configuration for N and N-3. How many electrons are in the valence energy level?

1 answer:

8 0

Non-valence electrons: 1s22s22p6. Therefore, we write the electron configuration for Na: 1s22s22p63s1. What is the highest principal quantum number that you see in sodium's electron configuration? It's n = 3, so all electrons with n = 3 are valence electrons, and all electrons with n < 3 are non-valence electrons.

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The breeding of animals is necessary to produce

Aneli [31]

Animal breeding is the process of selective mating of animals with desirable genetic traits, to maintain these traits in future generations.

6 0

3 years ago

Please help me!! thank you so much!!

Elis [28]

Answer:

13.75

Explanation:

gets halved every 8 days so halved twice

4 0

4 years ago

Name the particle that has each type of charge?

Zanzabum

Answer:

positive: proton

negative: electrons

no charge/nuetral: nuetron

Explanation:

no charge could be also described as nuetral.

3 0

3 years ago

Read 2 more answers

A hot air balloon filled with 1.27x10^6L of an ideal gas on a cool morning of 11 degrees C. the air is heated to 105 degrees C.

Elenna [48]

Answer:

New volume = $1.69\times 10^6$ L

Explanation:

Using Charle's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = $1.27\times 10^6$ L

V₂ = ?

T₁ = 11 °C

T₂ = 105 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (11 + 273.15) K = 284.15 K

T₂ = (105 + 273.15) K = 378.15 K

Using above equation as:

$\frac{1.27\times 10^6}{284.15}=\frac{V_2}{378.15}$

$V_2=\frac{1.27\times 10^6\cdot \:378.15}{284.15}$

New volume = $1.69\times 10^6$ L

8 0

4 years ago

When lithium nitride, Li3N(s) , is treated with water, H2O(l) , ammonia, NH3(g) , is produced. Predict the formula of the gas pr

Ronch [10]

Answer: The gas produced when sodium phosphide reacts with water is phosphine.

Explanation:

When sodium phosphide reacts with water molecule, it leads to the production of flammable, poisonous gas known as phosphine along with the production of sodium hydroxide.

The chemical reaction for the reaction of sodium phosphide with water follows the equation:

$Na_3P(aq.)+3H_2O(l)\rightarrow PH_3(g)+3NaOH(aq.)$

By Stoichiometry of the reaction:

1 mole of sodium phosphide reacts with 3 moles of water to produce 1 mole of phosphine gas and 3 moles of sodium hydroxide.

Hence, the gas produced when sodium phosphide reacts with water is phosphine.

7 0

4 years ago