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kari74 [83]
4 years ago
13

Given that one cup = 257.6 mL, calculate the molarity of vitamin C in orange juice.

Chemistry
1 answer:
iragen [17]4 years ago
8 0

Answer:

2.80 × 10⁻³ M

Explanation:

There is some info missing. I think this is the original question.

<em>One cup of fresh orange juice contains 127 mg of ascorbic acid (vitamin C, C₆H₈O₆). Given that one cup = 257.6 mL, calculate the molarity of vitamin C in orange juice. </em>

<em>Express your answer to an appropriate number of significant figures with the appropriate units.</em>

<em />

Step 1: Convert the mass of ascorbic acid to grams

We will use the relationship 1 g = 1,000 mg.

127mg \times \frac{1g}{1,000mg} = 0.127g

Step 2: Calculate the moles corresponding to 0.127 g of ascorbic acid

The molar mass of ascorbic acid is 176.13 g/mol.

0.127g \times \frac{1mol}{176.13g} = 7.21 \times 10^{-4} mol

Step 3: Convert the volume of the solution to liters

We will use the relationship 1 L = 1,000 mL.

257.6mL \times \frac{1L}{1,000mL} = 0.2576L

Step 4: Calculate the molarity of the solution

M = \frac{7.21 \times 10^{-4} mol}{0.2576L} = 2.80 \times 10^{-3} M

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We can check this answer since the time in the question is the double of this  half-life and the data shows the material has decayed by a fourth: two half-lives.

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But if a compound does not contain any charge then it means the compound is neutral.

For example, in the compound P_{4}O_{6} there is no charge so, this compound is neutral.

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Answer:

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