(a) Equating centripetal force to friction force, one finds the relation
v² = kar
for car speed v, coefficient of friction k, radius of curvature r, and downward acceleration a.
There is already downward acceleration due to gravity. The additional accceleration due to the wing is
a = F/m = 10600 N/(805 kg) ≈ 13.1677 m/s²
We presume this is added to the 9.80 m/s² gravity provides, so the coefficient of friction is
k = v²/(ar) = (54 m/s)²/((13.1677 m/s² +9.80 m/s²)·(155 m))
k ≈ 0.8191
(b) The maximum speed is proportional to the square root of the downward acceleration. Changing that by a factor of 9.80/(9.80+13.17) changes the maximum speed by the square root of this factor.
max speed with no wing effect = (54 m/s)√(9.8/22.97) ≈ 35.27 m/s
Answer:
Explanation:
vertical magnetic field B_v = 4 x 10⁻⁵ T.
Magnetic field due to horizontal current at point 20 cm above
= (μ₀/4π ) x (2i / R)
= 10⁻⁷ x 2 x 20/ 20 x 10⁻²
= 2 x 10⁻⁵ T
It will act coming out of paper. Hence it will be normal to magnetic field given .
So resultant magnetic field
= √ (4² + 2²) x 10⁻⁵ T
= 4.47 X 10⁻⁵ T .
Answer:When the image distance is positive, the image is on the same side of the mirror as the object, and it is real and inverted. When the image distance is negative, the image is behind the mirror, so the image is virtual and upright.
Explanation:
140 is the velocity because you need to multiply 40×2.5