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Goshia [24]
3 years ago
13

Calculate the expansion work done on the system when exactly 1 mol of solid ammonium chloride, nh4cl, decomposes completely to y

ield gaseous ammonia, nh3 and hydrogen chloride, hcl at a temperature of 1250 k. treat the expansion as irreversible and the gases formed as perfect.
Chemistry
1 answer:
maria [59]3 years ago
8 0

The expansion work on an irreversible system is equal to:

W = - PV

 

Assuming that the gas is ideal, therefore:

PV = nRT

 

[P=pressure, V=volume, n=number of moles, R=gas constant, T=absolute temperature]

 

Therefore,

W = -nRT

W = -(1 mol) * (8.314 J / mol K) * (1250 K)

W = -10,392.50 J

 

Therefore about 10,392.50 J or 10.4 kJ of work is done on the system.

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3 years ago
A rock that is made of coarse-grained particles arranged into bands is found. What type of rock is it?
Ne4ueva [31]
Igneous Rock because all those ingredients are in them

4 0
3 years ago
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Which energy resource causes the most safety concerns?.
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4 0
2 years ago
g The decomposition reaction of A to B is a first-order reaction with a half-life of 2.42×103 seconds: A → 2B If the initial con
Tanzania [10]

Answer:

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

Explanation:

The equation used to calculate the constant for first order kinetics:

t_{1/2}=\frac{0.693}{k}} .....(1)

Rate law expression for first order kinetics is given by the equation:

t=\frac{2.303}{k}\log\frac{[A_o]}{[A]} ......(2)

where,  

k = rate constant

t_{1/2} =Half life of the reaction = 2.42\times 10^3 s

t = time taken for decay process = ?

[A_o] = initial amount of the reactant = 0.163 M

[A] = amount left after time t =  66.8% of [A_o]

[A]=\frac{66.8}{100}\times 0.163 M=0.108884 M

k=\frac{0.693}{2.42\times 10^3 s}

t=\frac{2.303}{\frac{0.693}{2.42\times 10^3 s}}\log\frac{0.163 M}{0.108884 M}

t = 1,409.19 s

1 minute = 60 sec

t=\frac{1,409.19 }{60} min=23.49 min

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

6 0
3 years ago
What's the momentum of a 3.5-kg boulder rolling downhill at 5 m/s? A. 17.5 km·m/s B. 70 kg·m/s C. 8.5 kg·m/s D. 14.3 kg·m/s
swat32

Hey There!:


p = m * V


p = 3.5 * 5


p = 17.5 Km.m/s


Answer A


hope this helps!

7 0
3 years ago
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