J.j Thomson electrons demo true indivisible sphere n Ernest central nucleas
The dye molecules move in a directed way from high to low concentration
Explanation:
The statement that best describes the motion of dye molecule in water is directed from a region of high to low concentration. The motion of the particles of the dye in water is described as diffusion:
- diffusion is the movement of molecules of a substance from one position to another.
- diffusion occurs from a region of high concentration to that of a low concentration.
- the dye in the water solution causes an increase in concentration of an area where it is dropped.
- this causes the particles to spread outward in the solution.
- a concentration gradient is set up between the two parts of the solution.
- this gradient facilitates the movement of the dye particles.
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Answer:
e. all of these
Explanation:
Let us check all the given options one by one:
a.The nucleus is positively charged.
Yes it is correct since nucleus contain protons and neutrons and protons are positively charged.
b.The nucleus contains both charged and uncharged particles.
Yes because protons are positively charged and neutrons are neutral in nature.
c.The electrons contribute very little to the total mass of the atom.
Yes we know all the mass of the atom is considered in center and mass of electron is negligible as compared to protons and neutrons.
d.The electrons are located in the atomic space outside the nucleus.
Yes, its a known fact.
e. All of these.
Since , all given options are correct .
Therefore , option e. is right .
Molar mass:
Ag = 107.86 g/mol
Cu = 63.54 g/mol
Mole ratio:
Cu(s)+2 AgNO₃(aq)→Cu(NO₃)₂(aq)+2 Ag(s)
63.54 g Cu ------------- 2 x 107.86 g Ag
1.50 g Cu -------------- ??
Mass Ag = 1.50 x 2 x 107.86 / 63.54
Mass Ag = 32358 / 63.54
= 509.25 g of Ag
hope this helps!
Explanation:
1st one will be cathodic reaction and reduction will occur since electrons are being gained and hydrogen goes from +1 to zero oxidation state.
2nd one will be anodix reaction and oxidation will take place because Iodide ion's oxidation number increases from -1 to 0
