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pogonyaev
3 years ago
6

Why are open systems inappropriate for studying the conservation of mass?

Chemistry
1 answer:
Harrizon [31]3 years ago
5 0

Why are open systems inappropriate for studying the conservation of mass?? The sample may become contaminated. Matter may be created or destroyed within the system. Heat can escape from or enter the system. Matter may be lost to or gained from the surroundings.

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When 0.49 g of a molecular compound was dissolved in 20.00 g of cyclohexane, the freezing point of the solution was lowered by 3
IRISSAK [1]

Answer: The molecular mass of this compound is 131 g/mol

Explanation:

Depression in freezing point:

\Delta T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

\Delta T_f = depression in freezing point  = 3.9^oC

k_f = freezing point constant  = 20.8^0C/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute = 0.49 g

w_1 = mass of solvent (cyclohexane) = 20.00 g

M_2 = molar mass of solute = ?

Now put all the given values in the above formula, we get:

(3.9)^oC=1\times (20.8^oC/m)\times \frac{(0.49g)\times 1000}{M_2\times (20.00g)}

M_2=131g/mol

Therefore, the molar mass of solute is 131 g/mol

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