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3 years ago

What is the value of {-12} –13 –12 12 13

Mathematics

1 answer:

Serhud [2]3 years ago

4 0

Answer:

find it in this file bts/shah's.th

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Please help!! There’s 2 questions, Explain step by step pls :)

schepotkina [342]

Answer:

I'm late but the answer to the question on the left is 21 and the answer to the question on the right is 3.

Step-by-step explanation:

Remember that you have to complete the equations in order of PEMDAS.

19-3×4÷(-6)

For this equation, you would do 3×4 first (which equals 12) then divide that by -6 (Which equals - 2) and finally you would subtract that from 19. 19 - (-2)= 21

6(-8) / -12 - 1

For this equation you would do 6(-8) first (which equals -48) then divide that by -12 (which equals 4) and finally subtract 1 from that 4. 4-1=3

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3 years ago

Polygon P'Q'R'S'T' shown on the grid below is an image of polygon PQRST after dilation with a scale factor of 3, keeping the ori

Allushta [10]

Answer:

D is the answer

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3 years ago

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You are playing a solitaire game in which you are dealt three cards without replacement from a simplified deck of 10 cards (mark

g100num [7]

276 hands very simple im in 6th grade

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3 years ago

Can someone please help me asap?

pashok25 [27]

find the area the get the premiraterStep-by-step explanation:add

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3 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

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1 year ago