Why is it important to clearly define the coordinate system you want to use when analyzing objects in free fall

Physics

1 answer:

ddd [48]2 years ago

4 0

Answer:

Understanding projections and coordinate systems important knowledge to have, especially if you deal with many different sets of data that come from different sources. Projections Distortion Coordinate Systems Datums

A Cartesian coordinate system. Locations on the Earth's surface are measured and represented in terms of coordinates; a coordinate is a set of two or more numbers that specifies the position of a point, line, or other geometric figure in relation to some reference system.

• Check Layer Properties > Source > Spatial Reference to find out what coordinate system your data is in. If it says “Unknown Coordinate System” you definitely want to use the Define Projection tool. • The Define Projection tool will not make a copy of your data.

Math coordinates identify the location of a point on a graph or map. The ordered pair, (x,y) is the address of the point. The Cartesian coordinate system is the graph used to locate the point.

Explanation:

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If an airplane were traveling westward with a thrust force of 450 N and there was a headwind (drag) of 200 N, what would the res

Marat540 [252]

Answer:

The resulting net force on the airplane would be 250N.

Explanation:

It would be 250N because to find the amount of Newtons you would have to do 450 minus 200. 450 minus 200 equals 250. You can check by adding 200 plus 250 and it equals 450 the which is the "thrust".

6 0

2 years ago

Read 2 more answers

OSCilloscope shows wave starts cycle minimum 20 units reaches max of 100 units before completing 5 milliseconds what is relation

Vitek1552 [10]

Answer:

$T=0.02\ s$

$f=50\ Hz$

Explanation:

Given:

minimum amplitude at the start of oscillation cycle, $a_0=20\ unit$

the first maximum amplitude after the start of oscillation cycle, $a_{m1}=100\ units$

Time taken to reach from the first minima to the first maxima, $t=5\times 10^{-3}\ s$

As we know that an oscilloscope executes a wave cycle represented by a sine wave. So we can deduce that it has executed one-fourth of the cycle in going from the amplitude of 20 units to 100 units in 0.005 seconds.

<u>So the time taken to complete one cycle of the oscillation:</u>

$T=4\times 0.005$