Question

3. The ratio of milk water in 55 liters of Adultered milk is 7:4. How much water must be added to make the mixture Ratio of 7:6? a)5 liters b)10 liters c)15 liters

Answer 1

Answer:

The answer is B 10 L

Step-by-step explanation:

let milk and water in the mixture be 7x and 4x equal 55L

$7x + 4x = 55 \\ 11x = 55 \\ x = 5$

$7(5) = 35l \: milk \\ 4(5) = 20l \: water$

let x Liters of water he added so that the ratio is 7:6

$\frac{35l \: milk}{20l \: water + x} = \frac{7}{6}$

cross multiply

$35l \: milk \times 6 = (20l \: water + x)7 \\ 210l \: m= 140l \: w + 7x \\ 210l \: m - 140l \: w = 7x \\ 70l = 7x \\ \frac{70}{7} = \frac{7x}{7 } \\ x = 10 l \: water$