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Zolol [24]
3 years ago
12

A sample of gold (Au) has a mass of 45.39 g.

Chemistry
1 answer:
professor190 [17]3 years ago
8 0
<span>1. What is the molar mass of gold?
Molar mass is a unit that expresses the mass of a molecule per one mol. The molar mass can be obtained by adding the neutron with the proton of the atoms. Gold has atomic number 79 so the proton is 79. The number of the neutron is 118. Then the molar mass would be: 79 + 118 = </span>197 g/mol<span>


</span><span>2. Calculate the number of moles of gold (Au) in the sample. Show your work. 
</span>In this question, you are given the mass of the gold and asked for how many moles the sample has. To find the number of moles you just need to divide the weight by the molar mass.
For 45.39 grams of gold, the number of moles would be:
45.39 / (197g/mol)= 0.23 moles


3. Calculate the number of atoms of gold (Au) in the sample. Show your work.Moles is unit of a number of molecules but 1 mol doesn't represent 1 molecule. The number of atoms can be obtained by multiplying the number of moles with Avogadro number. The calculation would be:
0.23 moles * (6.023 * 10^23 molecules/mol)= 1.387 * 10^23 molecules
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Given the chemical equation: Fe2O3 + 3CO --&gt; 2Fe + 3CO2
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Answer:

The answer to your question is 160 g of Fe₂O₃  

Explanation:

Data

mass of Fe = 112 g

mass of CO = in excess

mass of Fe₂O₃ = ?

Balanced chemical reaction

                Fe₂O₃  +  3CO  ⇒  2Fe  +  3CO₂

Process

1.- Calculate the molar mass of Fe₂O₃ and Fe

Molar mass Fe₂O₃ = (56 x 2) + (16 x 3) = 112 + 48 = 160 g

atomic mass of Fe = 56

2.- Use proportions to calculate the mass of Fe₂O₃ needed

                160 g of Fe₂O₃ ------------------- 2(56) g of Fe

                 x     g of Fe₂O₃ ------------------ 112 g of Fe

                 x = (112 x 160) / 2(56)

                 x = 17920/112

                 x = 160 g of Fe₂O₃          

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