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Vinil7 [7]
3 years ago
6

The diagram shows Niels Bohr’s model of an atom.

Chemistry
2 answers:
miskamm [114]3 years ago
5 0

Answer:

Energy is absorbed by the atom.

Explanation:

PtichkaEL [24]3 years ago
4 0

Answer:

Energy is absorbed, and an emission line is produced.

Explanation:

Electrons are present and revolving continuously in the orbits that are present around the nucleus. The energy of electron are fixed and unable to move to other orbits due to the strong attractive force of the proton which is present in the nucleus of the atom. If the electron wants to jump from the first energy level to the second energy level, so the electron has to absorb enough energy which can overcome the attractive force of proton.

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Complete the acid–base equation for the dissolution of the following compound into liquid HF solvent. The relevant pKa values ar
LenKa [72]

Answer:

The balanced chemical equation: NH₃ + 2 HF → NH₄⁺ + HF₂⁻

Explanation:

According to the Brønsted–Lowry acid–base theory, the acid- base reaction is a type of chemical reaction between the acid and base to give a conjugate acid and a conjugate base.

In this reaction, a Brønsted–Lowry acid loses a proton to form a conjugate base. Whereas, a Brønsted–Lowry base accepts a proton to form a conjugate acid.

Acid + Base ⇌ Conjugate Base + Conjugate Acid

The acid dissociation constant (Kₐ) <em>signifies the acidic strength of a chemical species.</em>

∵ pKₐ = - log Kₐ

Thus for a strong acid, Kₐ value is large and pKₐ value is small.

pKₐ (HF) = 3.2 → strong acid

pKₐ (NH₃) = 38 → weak acid

<u>The chemical reaction involved in the dissolution process:</u>

NH₃ + 2 HF → NH₄⁺ + HF₂⁻

In this acid-base reaction, the acid HF reacts with NH₃ base to give the conjugate base HF₂⁻ and conjugate acid NH₄⁺.

<u>HF (acid) donates a proton to form the conjugate base, HF₂⁻ ion. NH₃ (base) accepts a proton to form the conjugate acid. </u>

7 0
3 years ago
Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L
8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's  Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure  of component A is P_A and vapour pressure of component B is P_B.

P^0_A= Vapour pressure of component A in pure form

P^0_B= Vapour pressure of component B in pure form

x_A=Mole fraction of component A

x_B==Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

P_A >P^0_A\cdot x_A,P_B>P^0_B\cdot x_B

Therefore, P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B

Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.

Hence, option a,b,c and d are true.

6 0
3 years ago
If the acceleration is 600 m/s/s and the mass is 300 kg, what force is acting on the object?
vampirchik [111]

Explanation:

Acceleration (a) = 600 m/s²

Mass (m) = 300 kg

Force (F) = ?

We know

F = m * a

= 300 * 600

=180000 Newton

The force acting on the object is 18000 Newton.

5 0
3 years ago
Read 2 more answers
PLEASE HELP!
Anon25 [30]

Answer:

C. Mole

Explanation:

Chemical formula deals with mole number

4 0
3 years ago
1. As you increase speed is there an increase or decrease in Kinetic Energy?
drek231 [11]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

1. As you increase speed is there an increase or decrease in Kinetic Energy?

\qquad \sf  \dashrightarrow \: increase

2. As you increase mass is there an increase or decrease in Kinetic Energy?

<h3 />

\qquad \sf  \dashrightarrow \: increase

3. As you decrease speed is there an increase or decrease in Kinetic Energy?

\qquad \sf  \dashrightarrow \: decrease

4. As you decrease mass is there an increase or decrease in Kinetic Energy?

\qquad \sf  \dashrightarrow \: decrease

3 0
3 years ago
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