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Korolek [52]
3 years ago
8

Regions that receive up to 20 inches of rainfall per year are referred to as __________ because they receive more precipitation

than most deserts.
semiarid deserts


polar deserts


coastal deserts


subtropical deserts
Chemistry
1 answer:
UNO [17]3 years ago
8 0

Answer:

semiarid deserts

Explanation:

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Science experiments usually include an independent variable, dependent variable, and control. ... Science experiments also include something called constants. A constant is the part that doesn't change during the experiment.
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Calculate the pH for the following weak acid. A solution of HCOOH has 0.12M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4.
Shtirlitz [24]

Answer:

the pH of HCOOH solution is 2.33

Explanation:

The ionization equation for the given acid is written as:

HCOOH\leftrightarrow H^++HCOO^-

Let's say the initial concentration of the acid is c and the change in concentration x.

Then, equilibrium concentration of acid = (c-x)

and the equilibrium concentration for each of the product would be x

Equilibrium expression for the above equation would be:

\Ka= \frac{[H^+][HCOO^-]}{[HCOOH]}

1.8*10^-^4=\frac{x^2}{c-x}

From given info, equilibrium concentration of the acid is 0.12

So, (c-x) = 0.12

hence,

1.8*10^-^4=\frac{x^2}{0.12}

Let's solve this for x. Multiply both sides by 0.12

2.16*10^-^5=x^2

taking square root to both sides:

x=0.00465

Now, we have got the concentration of [H^+] .

[H^+] = 0.00465 M

We know that, pH=-log[H^+]

pH = -log(0.00465)

pH = 2.33

Hence, the pH of HCOOH solution is 2.33.

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Hydrogen bonds between water molecules are responsible for the unique chemical and physical properties of water. True False
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Answer:

True

Explanation:

The physical and chemical properties of a substance depend on the nature of intermolecular forces between its molecules. For instance, water has a high boiling point because of hydrogen bonding between water molecules. Liquid water is denser than ice because of the difference in the nature of hydrogen bonding in liquid water and ice.

3 0
3 years ago
a sample of argon gas is cooled and its volume went from 380. mL to 250. mL. If its final temperature was -55.0C, what was its o
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Answer:

The initial temperature was 58.4°C

Explanation:

Given the following data:

initial volume = V₁ = 380 mL = 0.38 L

final volume = V₂ = 250 mL = 0.25 L

final temperature = T₂ = -55°C = 218 K

According to Charles's law, the volume of a gas is <em>directly proportional to the temperature</em> (in Kelvin). The mathematical expression is:

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So, we calculate the initial temperature (V₁) as follows:

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Finally, we convert the initial temperature from K to °C:

T₁= 331.4 K - 273 = 58.4°C

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