All categories

3 years ago

A tennis player practices against a wall, hitting a 0.1 kg ball towards the

Physics

1 answer:

pantera1 [17]3 years ago

3 0

Answer: 80 Newton

Explanation:

Initial velocity of ball = +20 m/s.

Final velocity of ball = -20 m/s

Mass of ball = 0.1kg

Time taken = 0.05 seconds

Average force = (Change in momentum of moving ball / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum =0.1 x (-20 - (+20))

= 0.1 x (-20-20)

= 0.1 x (-40)

= -4.0 kgm/s

Then, put -4.0 kgm/s in the equation of force when Average Force = (Change in momentum / Time taken)

= (-4.0kgm/s / 0.05 seconds)

= 80Newton (note that the negative sign does not reflect on the magnitude of force)

Thus, the average force exerted on the ball is 80N

You might be interested in

Tulongan nyo ko guys

Whitepunk [10]

Ahhhh this is a USA server not philipino server so yeah sorry

6 0

3 years ago

How does a fixed pulley act as a machine?

anastassius [24]

<span>it changes the direction of the input force only

</span>

5 0

4 years ago

Read 2 more answers

Helium gas is in a cylinder that has rigid walls. If the pressure of the gas is 2.00 atm, then the root-mean-square speed of the

aivan3 [116]

Answer:

$p=p_{2}-p_{1}=2.9188atm$

Explanation:

First step

To calculate by how much the pressure has been increased we must find a relation between Vrms and the pressure p

$V_{rms}=\sqrt{\frac{3RT}{M} } \\$

Where M is molar mass,R is gas constant and T is temperature

As R and M is constant so we obtain

Vrams∝√T

Second step

From Ideal gas law we know that

$pV=nRT\\$

we will find that

p∝T

So from first and second step, we can obtain that

Vrms∝√p

And a relation between both of them could be given by:

$\frac{V_{rms1} }{V_{rms2}}=\frac{\sqrt{p_{1} } }{\sqrt{p_{2}} }\\ p_{2}=[\frac{(V_{rms1})^{2} }{(V_{rms2})^{2} }]p_{1}\\ p_{2}=\frac{(276m/s)^{2} }{(176m/s)^{2} } (2atm)\\p_{2}=4.9188atm$

The pressure is increased to 4.1988 atm, so the amount will be given by:

$p=p_{2}-p_{1}=4.9188atm-2atm\\p=p_{2}-p_{1}=2.9188atm$

7 0

3 years ago

Choose the COST tab and check that 1 day is selected. Set the Cost of electricity to 10.0 ¢/kWh. The daily cost is equal to the

AveGali [126]

Answer:

Daily Cost = 24 ¢

Explanation:

Consider a typical incandescent bulb having a power rating of 100 W. Now, we calculate the daily consumption by multiplying the Power with time:

Daily Consumption = (Power Rating)(Time in hours)

Daily Consumption = (0.1 KW)(24 h/1 day)

Daily Consumption = 2.4 KWh

Now, we will calculate the daily cost of the incandescent lamp by multiplying the daily consumption with the unit cost.

Daily Cost = (Daily Consumption)(Unit Cost)

Daily Cost = (2.4 KWh)(10 ¢/KWh)

<u>Daily Cost = 24 ¢</u>

6 0

3 years ago

What is the length of the space the rope on a pulley is moved called?

IgorLugansk [536]

4444b5b56bbb 6 6 6 7 8 8 8 8 8

4 0

4 years ago