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Anna71 [15]
3 years ago
6

An object is pulled up an incline plane at a constant velocity as the picture above shows. Calculate the tension on the rope.

Physics
1 answer:
WARRIOR [948]3 years ago
6 0

Hi there!

\large\boxed{545N}

Since the object is being pulled at a constant velocity, the forces must be balanced.

Since there is no movement vertically, we must take into account the horizontal forces. We can also assume a positive acceleration to be in the direction of motion.

The acceleration and force due to gravity on an incline is:

a = gsinФ

F = MgsinФ

∑F = -MgsinФ + T

Since it is getting pulled at a constant velocity, ∑F = 0. So:

0  = -MgsinФ + T

MgsinФ = T

Solve for T by plugging in values. Let g = 10 m/s²

T = (120)(10)sin(27) ≈ 545 N

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Magnetic dipole moment will be15.51\times 10^{-3}J/T

Explanation:

We have given length of the cylinder , that is h = 5.51 cm = 0.051 m

And diameter of the cylinder d = 0.865 cm

So radius r=\frac{d}{2}=\frac{0.865}{2}=0.4325cm=0.4325\times 10^{-2}m

So volume of cylinder V=\pi r^2h=3.14\times (0.4325\times 10^{-2})^2\times 0.051=3\times 10^{-6}m^3

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