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zepelin [54]
2 years ago
14

A simple pendulum is suspended from the ceiling of a stationary elevator, and the period is determined.(i) When the elevator acc

elerates upward, is the period (a) greater(b) smaller(c) unchanged?
Physics
1 answer:
ELEN [110]2 years ago
6 0

The correct option is (a) greater.

<h3>What is simple pendulum?</h3>

A weight hanging from a pivot such that it may freely swing is called a pendulum. Gravity's restoring force will cause a pendulum to accelerate back toward its equilibrium position if it is sideways moved from its resting, equilibrium position.

The effective acceleration of the pendulum is equal to the sum of the acceleration caused by gravity and the elevator's upward acceleration while the elevator is moving upward.

T=2π√L/g(eff)

T=2π√L/(g+a)

Therefore, effective acceleration increases, and which results in a decrease in the period of motion.

to learn more about simple pendulum go to -

brainly.com/question/26449711

#SPJ4

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Two hover pucks collide in an off-centered collision and stick to one another via velcro. When they do so, they rotate in place.
Tpy6a [65]

Answer:

They will rotate twice as fast

Explanation:

Angular momentum is product of

m=  mass,

v=velocity

and

r= radius.

i-e

Angula Momentum = m×v×r=mvr

<u>If we increase mass</u>

Here we replace m with 2m and keep the size same i-e radius is kept constant !

==> Angular Momentum = 2m×v×r=2mvr

7 0
3 years ago
In this section of a circuit, a current of 2.6 A flows across R1. What is the potential difference V between point x and point y
Ymorist [56]

Answer:

V=21V

Explanation:

In series combination current is same

I=2.6A

R2=8ohm

V2=2.6×8

V2=20.8

V2=21V

5 0
3 years ago
What causes light to bend when it moves from one transparent medium to another?
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3 years ago
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A school bus has a mass (including the driver and passengers) of 1.64 times 10^4 kg and is driving north at a speed of 15.2 km/h
Butoxors [25]

Answer:

Explanation:

Given

mass of bus along with travelers travelling in North direction is m_1=1.6\times 10^4 kg

speed of bus towards North v_1=15.2 km/h\approx 4.22\ m/s

mass of bus travelling in South direction is m_2=1.578\times 10^4 kg

speed of bus v_2=12.2 km/h\approx 3.38\ m/s

mass of each Passenger in south moving bus m_0=64.8 kg

Momentum of North moving bus

P_1=m_1\times v_1

P_1=1.6\times 10^4\times 4.22

P_1=6.768\times 10^4 kg-m/s

Momentum with south moving bus

P_2=m_2\times v_2+n\cdot m_0\times v_2

P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38

For total momentum to be towards south

P_2-P_1 should be greater than 0

thus for least value of n

P_2=P_1

(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4

1.578\times 10^4+n\cdot 64.8=2.0023\times 10^4

n=\frac{4243.6686}{64.8}=65.48\approx 66    

5 0
3 years ago
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