Answer:
The correct answer is - B. Increase the time it takes to stop the egg once it hits his hand.
Explanation:
In order to catch the egg the force and time makes an impulse to the egg to change its momentum and bring it to rest. In order to change the momentum, one needs to decrease the force exerted onto the egg and increase the time it takes to make it rest.
Less force can be given to the egg by increasing the time to bring it to rest stop the egg once it hits his hand. Other than this it should be caught to the sides.
Explanation:
The frequency of an organ pipe if it is open is given by :
v is speed of sound in air is 343 m/s at 20°C
For fundamental frequency, n = 1
First overtone frequency,
Second overtone frequency,
Third overtone frequency
Hence, this is the required solution.
a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how
long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175
s this is the time to fall from the top; it would take the same time to travel
upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175
= 0.35s
b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice
to solve this problem the time it takes to fall the final 0.13 m is: time it
takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to
fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it
takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m
is then twice this, or 0.08s
Answer:
UP TO four inches but usually a little slower than that
Explanation:
