The total force that the SUV exerts is:
F = 2000 kg * 3 m/s^2
F = 6000 N
Since a resisting force amounting to 1500 N is exerted,
then the force exerted by the SUV tires is:
F tire = 6000 N – 1500 N
F tire = 4500 N
The final velocity of the truck is found as 146.969 m/s.
Explanation:
As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.
Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

Then, the final velocity will be

Thus, the final velocity of the truck is found as 146.969 m/s.
Displacement = 0, assuming that he runs back to original position
Average velocity is displacement/ time, since displacement =0, velocity is also 0
Answer:
It is destroyed in subduction zones. A Geologic process in which a tectonic plate made of dense lithospheric material melts or falls below a plate made of less-dense lithosphere at a convergent plate boundary
Explanation:
Hope this helps (: