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zepelin [54]
2 years ago
14

A simple pendulum is suspended from the ceiling of a stationary elevator, and the period is determined.(i) When the elevator acc

elerates upward, is the period (a) greater(b) smaller(c) unchanged?
Physics
1 answer:
ELEN [110]2 years ago
6 0

The correct option is (a) greater.

<h3>What is simple pendulum?</h3>

A weight hanging from a pivot such that it may freely swing is called a pendulum. Gravity's restoring force will cause a pendulum to accelerate back toward its equilibrium position if it is sideways moved from its resting, equilibrium position.

The effective acceleration of the pendulum is equal to the sum of the acceleration caused by gravity and the elevator's upward acceleration while the elevator is moving upward.

T=2π√L/g(eff)

T=2π√L/(g+a)

Therefore, effective acceleration increases, and which results in a decrease in the period of motion.

to learn more about simple pendulum go to -

brainly.com/question/26449711

#SPJ4

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A car traveling 34 mi/h accelerates uniformly for 4 s, covering 615 ft in this time. What was its acceleration? Round your answe
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Answer:

51.94 ft/s²

257.63 ft/s

Explanation:

t = Time taken = 4 s

u = Initial velocity = 34 mi/h

v = Final velocity

s = Displacement = 615 ft

a = Acceleration

Converting velocity to ft/s

34\ mi/h=\frac{34\times 5280}{3600}=49.87\ ft/s

Equation of motion

s=ut+\frac{1}{2}at^2\\\Rightarrow a=2\frac{s-ut}{t^2}\\\Rightarrow a=2\left(\frac{615-49.87\times 4}{4^2}\right)\\\Rightarrow a=51.94\ ft/s^2

Acceleration is 51.94 ft/s²

v=u+at\\\Rightarrow v=49.87+51.94\times 4\\\Rightarrow v=257.63\ ft/s

Final velocity at this time is 257.63 ft/s

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