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Murrr4er [49]
3 years ago
11

The distance traveled by an object can be modeled by the equation d = ut + 0.5at2 where d = distance, u = initial velocity, t =

time, and a = acceleration. Solve this formula for a. Show all steps in your work. plz someone >~<.
Physics
1 answer:
Taya2010 [7]3 years ago
8 0
We are given with the expression d = ut + 0.5 at^2 and is asked to express the equation in terms of a. First, we transpose ut to the left side, then we multiply to the equation and divide lastly the resulting equation by t^2. The final expression becomes a = 2(d-ut)/t^2.
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This is a form of energy representing the motion of the molecules which make up an object. A. Thermal Energy B. Kinetic Energy C
bija089 [108]

Answer:

Kinetic energy.

Explanation:

  • There are many kinds of energy. Some of them are kinetic energy, potential energy, thermal energy etc.
  • The energy that shows the motion of the object is called its kinetic energy.
  • Also, the sum of kinetic energy and the gravitational potential energy is called mechanical energy.
  • Out of the given options, kinetic energy is the form of energy that represents the motion of the molecules which make up an object.
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4 0
3 years ago
¿Qué cantidad de calor absorbió una masa de 4 g de cinc al pasar de 20 °C a<br> 180 °C?
Alborosie

(amount of heat)Q = ? , (Mass) m= 4 g , ΔT = T f - T i = 180 c° - 20 °c = 160 °c ,

Ce = 0.093 cal/g. °c

Q = m C ΔT

Q = 4 g × 0.093 cal/g.c° × ( 180 °c- 20 °c )

Q= 4×0.093 × 160

Q = 59.52 cal

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2 years ago
a battery is tested and it is found that the voltage Vout = 1.64V with the switch open and 1.63V with the switch closed. Find th
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Our galaxy, the ______________, contains more than 200 billion stars.
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4 0
3 years ago
A 0.325 g wire is stretched between two points 57.7 cm apart. The tension in the wire is 650 N. Find the frequency of first harm
Galina-37 [17]

Answer:

f = 931.1 Hz

Explanation:

Given,

Mass of the wire, m = 0.325 g

Length of the stretch, L = 57.7 cm = 0.577 m

Tension in the wire, T = 650 N

Frequency for the first harmonic = ?

we know,

v =\sqrt{\dfrac{T}{\mu}}

μ is the mass per unit length

μ = 0.325 x 10⁻³/ 0.577

μ = 0.563 x 10⁻³ Kg/m

now,

v =\sqrt{\dfrac{650}{0.563\times 10^{-3}}}

   v = 1074.49 m/s

The wire is fixed at both ends. Nodes occur at fixed ends.

For First harmonic when there is a node at each end and the longest possible wavelength will have condition

          λ=2 L

          λ=2 x 0.577 = 1.154 m

we now,

       v = f λ

      f = \dfrac{v}{\lambda}

      f = \dfrac{1074.49}{1.154}

             f = 931.1 Hz

The frequency for first harmonic is equal to f = 931.1 Hz

7 0
3 years ago
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