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vladimir1956 [14]

3 years ago

8

What is the mass of an object that requires 100N of force in order to accelerate it at 10m/s2 ?

2 answers:

Debora [2.8K]3 years ago

7 0

Answer:

We know that f=ma

Rearranging

M=f÷a so m=10kg

Explanation:

jeka57 [31]3 years ago

3 0

<u>Answer:</u> The mass of an object is 10 kg.

<u>Explanation:</u>

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

$F=ma$

where,

F = force exerted on the object = 100 N

m = mass of the object = ?

a = acceleration of the object = $10m/s^2$

Putting values in above equation, we get:

$100kg.m/s^2=m\times 10m/s^2\\\\m=\frac{100}{10}=10kg$

Hence, the mass of an object is 10 kg.

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How much salt (nacl) is carried by a river flowing at 30.0 m3/s and containing 50.0 mg/l of salt? give your answer in kg/day?

slamgirl [31]

Answer: 129,600kg/day
In this question, you are given the river flow (30m3/s) and the salt concentration. Then to determine the amount of salt carried, you simply need to multiply the flow with concentration. Be careful because the unit in this question is different and need to be converted. The equation would be:

Salt = river flow x salt concentration
Salt = 30m3/s x 1000L/m3 x 50mg/L = 1,500,000mg/second

Then convert it into kg/day
Salt= 1,500,000mg/second x 10^-6 kg/mg x (3600 second/hour) x (24 hour/day)= 129,600kg/day

7 0

3 years ago

When cooking frozen cheese ravioli, the directions say to put the 255 grams of filled pasta into 3 quarts of boiling water. Why

nadya68 [22]

Answer:

a. $T_f=95.14^{\circ}C$

b. $T_f=86.4^{\circ}C$

It is asked for 3 quarts of water because it prevents the temperature drop.

Explanation:

Given:

mass of frozen cheese, $m_c=255\ g$

quantity of water suggested for the given cheese, $m_w=3\ quarts\times 946.35=2839.05\ g$

initial temperature of cheese, $T_{ic}=-40^{\circ}\ C$

specific heat of cheese, $c_c=0.4\ cal.g^{-1}.^{\circ}C^{-1}$

initial temperature of water, $T_{iw}=100^{\circ}\ C$

a.

we have specific heat of water, $c_w=1\ cal.g^{-1}.^{\circ}C^{-1}$

so now, we use the heat equation to find the amount of heat exchange during the process:

$m_c\times c_c\times \Delta T=m_w\times c_w\times \Delta T$

$255\times 0.4\times (T_f-(-40))=2839.05\times 1\times (100-T_f)$

$T_f=95.14^{\circ}C$

b.

when using 1 quart of water:

$255\times 0.4\times (T_f-(-40))=946.35\times 1\times (100-T_f)$

$T_f=86.4^{\circ}C$

It is asked for 3 quarts of water because it prevents the temperature drop.

3 0

3 years ago

Line segment gj is a diameter of circle l. angle k measures (4x 6)°. circle l is inscribed with triangle g j k. line segment g j

choli [55]

The value of x in the given right triangle in a semicircle is determined as 21.

<h3>What is the measure of a triangle in a semicircle?</h3>

The triangle in a semicircle is always a right angle triangle.

From the figure shown, we can say that the triangle G J K is right triangle and m<K = 90degrees.

Given that m<K = 4x + 6, we will can use the following equation to find the value of x as shown:

4x + 6 = 90

4x = 90 - 6

4x = 84

x = 21

Thus, the value of x in the given right triangle in a semicircle is determined as 21.

Learn more about right angle here: brainly.com/question/64787

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8 0

2 years ago

Please help im failing!!!

natta225 [31]

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5 0

3 years ago

where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the work

goldenfox [79]

Answer:

Both

Explanation:

8 0

3 years ago