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olga nikolaevna [1]
2 years ago
13

(a) Sabbir usually (sit)______ in the front bench.

Engineering
1 answer:
klasskru [66]2 years ago
5 0

Answer:

a)sits

b)is shining

d)have been living

Explanation:

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Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 76 vol% carbide
Georgia [21]

Answer:

The answer is below

Explanation:

Given that:

Volume of carbide (V_{C}) = 76% = 0.76, Volume of Nickel (V_{M}) = 100% - 76% = 24% = 0.24, thermal conductivities of carbide (E_{C}) = 30 W/m-K and thermal conductivities of meta. (E_M) = 67 W/m-K

a) The maximum thermal conductivity is given by:

Max = E_CV_c+E_mV_m=(0.76*30) + (0.24*67) = 38.88\ W/mK

b) The minimum thermal conductivity is given by:

Min = \frac{E_ME_C}{E_MV_C+E_CV_M}=\frac{30*67}{(0.76*67)+(0.24*30)}=34.58\ W/mK

8 0
2 years ago
Name the important trees of tropical monsoon forest​
mars1129 [50]
Sal, Teak, Bamboo and Myrobalan
8 0
3 years ago
Air flows through a device such that the stagnation pressure is 0.4 MPa, the stagnation temperature is 400°C, and the velocity i
RoseWind [281]

To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.

The stagnation temperature can be defined as

T_0 = T+\frac{V^2}{2c_p}

Where

T = Static temperature

V = Velocity of Fluid

c_p = Specific Heat

Re-arrange to find the static temperature we have that

T = T_0 - \frac{V^2}{2c_p}

T = 673.15-(\frac{528}{2*1.005})(\frac{1}{1000})

T = 672.88K

Now the pressure of helium by using the Adiabatic pressure temperature is

P = P_0 (\frac{T}{T_0})^{k/(k-1)}

Where,

P_0= Stagnation pressure of the fluid

k = Specific heat ratio

Replacing we have that

P = 0.4 (\frac{672.88}{673.15})^{1.4/(1.4-1)}

P = 0.399Mpa

Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa

<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>

3 0
2 years ago
The current through a 10-mH inductor is 10e−t∕2 A. Find the voltage and the power at t = 8 s.
NNADVOKAT [17]

Answer:

voltage = -0.01116V

power = -0.0249W

Explanation:

The voltage v(t) across an inductor is given by;

v(t) = L\frac{di(t)}{dt}             -----------(i)

Where;

L = inductance of the inductor

i(t) = current through the inductor at a given time

t = time for the flow of current

From the question:

i(t) = 10e^{-t/2}A

L = 10mH = 10 x 10⁻³H

Substitute these values into equation (i) as follows;

v(t) = (10*10^{-3})\frac{d(10e^{-t/2})}{dt}

Solve the differential

v(t) = (10*10^{-3})\frac{-1*10}{2} (e^{-t/2})

v(t) = -0.05 e^{-t/2}

At t = 8s

v(t) = v(8) = -0.05 e^{-8/2}

v(t) = v(8) = -0.05 e^{-4}

v(t) = -0.05 x 0.223

v(t) = -0.01116V

(b) To get the power, we use the following relation:

p(t) = i(t) x v(t)

Power at t = 8

p(8) = i(8) x v(8)

i(8) = i(t = 8) = 10e^{-8/2}

i(8) = 10e^{-4}

i(8) = 10 x 0.223

i(8) = 2.23

Therefore,

p(8) = 2.23 x -0.01116

p(8) = -0.0249W

7 0
3 years ago
Read 2 more answers
According to the zeroth law of thermodynamics, which of the following cannot occur?
Ierofanga [76]

Answer:

Answer is B       A cooler full of ice chilling a soda sitting on top of it

Explanation:

A cooler full of ice chilling a soda sitting on top of it

3 0
3 years ago
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