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ArbitrLikvidat [17]
3 years ago
13

How many electrons do atoms like to have in their outer shell?

Chemistry
1 answer:
irakobra [83]3 years ago
7 0

Explanation:

In general, atoms are most stable, least reactive, when their outermost electron shell is full. Most of the elements important in biology need eight electrons in their outermost shell in order to be stable, and this rule of thumb is known as the octet rule.

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Im doing a science fair project and i need to find out what are the constents in my project i have to presnt tomorrow i need hel
lions [1.4K]
The constents would be anythign that stays the same in ever experiment. 

Example:  Growing sunflowers in different liquids 

The constants could be: Type of dirt used to grow each, amount of liquid used to water, and the type of sunflowers grown. 


4 0
3 years ago
The Haber reaction for the manufacture of ammonia is: N2 + 3H2 → 2NH3 Without doing any experiments, which of the following can
Dimas [21]

Answer :  The correct statement is, \text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

The expression for rate of reaction :

\text{Rate of disappearance of }N_2=-\frac{d[N_2]}{dt}

\text{Rate of disappearance of }H_2=-\frac{1}{3}\frac{d[H_2]}{dt}

\text{Rate of formation of }NH_3=+\frac{1}{2}\frac{d[NH_3]}{dt}

From this we conclude that,

\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

Hence, the correct statement is, \text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

3 0
4 years ago
With newtons cradle , will the balls rock back-and-forth forever on the moon? Explain in detail.
LUCKY_DIMON [66]
No because it has less gravity and there is nothing that can run forever eventually the strings will wear out or the balls would stop
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6 0
4 years ago
For the following reaction, 2.45 grams of methane (CH4) are allowed to react with 27.7 grams of carbon tetrachloride . methane (
rosijanka [135]

Answer:

The limiting reactant is CH₄

26.0g of CH₂Cl₂ is the maximum amount that can be formed

4.15g CCl₄ will remain

Explanation:

The reaction of methane, CH₄, with carbon tetrachloride, CCl₄ is:

CH₄ + CCl₄ → 2CH₂Cl₂

To find the maximum mass of dichloromethane that can be determined we need to find moles of methane and carbon tetrachloride:

<em>Moles CH₄:</em>

2.45g * (1mol / 16.04g) = 0.153 moles

<em>Moles CCl₄:</em>

27.7g * (1mol / 153.82g) = 0.180 moles

That means just 0.153 moles of CCl₄ will react until CH₄ is over.

<em>The limiting reactant is CH₄</em>

<em />

Assuming the whole 0.153 moles will react, the moles of CH₂Cl₂ will be:

0.153 moles CH₄ * (2 moles CH₂Cl₂ / 1 mole CH₄) = 0.306 moles of CH₂Cl₂

The mass is (Molar mass dichloromethane: 84.93g/mol):

0.306 moles of CH₂Cl₂  * (84.93g / mol) = 26.0g of CH₂Cl₂

The moles of CCl₄ that remain are:

0.180 moles - 0.153 moles = 0.027 moles

In grams:

0.027 moles * (153.82g / mol) = 4.15g CCl₄

3 0
3 years ago
Why is important to use the same ink dots for both the alcohol and oil experiments?
patriot [66]
So you don’t mess it up
3 0
3 years ago
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