*URGENT 20 POINTS*
1 answer:
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The equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
<h3>How to determine the legs of the triangle?</h3>The complete question is in the attached image
The given parameters are:
Area = 24
Legs = x and x + 2
The area of the triangle is calculated as:
Area = 0.5 * Base * Height
This gives
0.5 * x * (x + 2) = 24
So, we have:
0.5(x)(x + 2) = 24
Divide through by 0.5
(x)(x + 2) = 48
Expand
x^2 + 2x = 48
Subtract 48 from both side
x^2 + 2x - 48 = 0
Hence, the equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
Read more about area at:
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Step-by-step explanation:
<u>Answer(1):</u>
Law of Cosines.
<u>Answer(2):</u>
since side "c" is missing so we will write formula used for side "c"
<u>Answer(3):</u>
First lets write both sine and cosine formulas:
Check the attached picture for the list of formulas:
From given picture we see that two angles A and B are missing. Also 1 side "c" is missing.
Sine formula uses two angles while cosine formula uses only one angles.
Hence cosine formula will be best choice to find the missing values.
Answer:
Here is the graph I made, starting from (-3,1) to (-2,-1) it goes down 2 units and over 1 unit.
