Milk is an example of solid emulsion. Hence, option D is correct.
<h3>What is emulsion?</h3>
An emulsion is defined as a colloid consisting of two or more non-homogenous type of liquids in which one of the liquid contains the dispersion of the different form of liquids.
Emulsion consist of a dispersion of two liquids that are immiscible with each other.
One of the liquids act as the dispersion medium and the other will act as the dispersed phase.
Emulsions are colloids in which both the dispersed phase and dispersion medium are liquids.
Types of Emulsion:
- Oil in water (O/W)
- In this type of emulsion, the oil will be the dispersed phase and water will be the dispersion medium.
- Example of o/w emulsion is milk.
2. Water in oil (W/O)
- In this type, water will be the dispersed phase and oil will be the dispersion medium.
- Margarine is an example of water in oil emulsion.
Milk is an example of solid emulsion. Hence, option D is correct.
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The formula you need is: heat= specific heat x mass x ΔT
specific heat= 0.46 j/g-C
mass= 100.0 grams
ΔT= 40.2 - 15.0= 25.2C
heat= (0.46) x (100.0) x (25.2)= 1159.2 joules or 1200 joules (rounded off)
A heterogeneous Mixture discribes a substance made of different kinds of atoms bonded together.
The answer is: [D]: " 417 cm³ " .
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Explanation: Use the formula:
V₁ /T₁= V₂ /T₂ ;
in which: V₁ = initial volume = 556 cm³ ;
T₁ = initial temperature = 278 K ;
V₂ = final ("new") temperature = 308 K
T₂ = final ("new:) volume = ?
Solve for "V₂" ;
Since: V₁ /T₁= V₂ /T₂ ;
We can rearrange this "equation/formula" to isolate "V₂" on one side of the equation; and then we can plug in our know values to solve for "V₂" ;
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V₁ /T₁= V₂ /T₂ ; Multiply EACH side of the equation by "T₂ " :
→ T₂ (V₁ /T₁) = T₂ (V₂ /T₂) ;
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to get:
↔ T₂ (V₂ /T₂) = T₂ (V₁ /T₁) ;
→ V₂ = T₂ (V₁ /T₁) ;
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Now, plug in our known values, to solve for "V₂" ;
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→ V₂ = T₂ (V₁ /T₁) ;
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→ V₂ = 308 K ( 556 cm³ /278 K) ;
→ The units of "K" cancel to "1" ; and we have:
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→ V₂ = 308*( 556 cm³ / 278 ) = [(208 * 556) / 278 ] cm³ ;
Note: We will keep the units of volume as: "cm³ "; since all the answer choices given are in units of: "cm³ " ; {that is, "cubic centimeters"}.
→ [(208 * 556) / 278 ] cm³ = [ (115,648) / (278) ] cm³ ;
→ For the "(115,648)" ; round to "3 (three significant figures)" ;
→ "(115,648)" → rounds to: "116,000" ;
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→ (116,000) / (278) = 417.2661870503597122 ;
→ round to 3 significant figures; → "417 cm³ " ;
→ which corresponds with "choice [D]".
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The answer is: [D]: "417 cm³ " .
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