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lakkis [162]
2 years ago
5

6x – 3y = 8

Mathematics
1 answer:
Nat2105 [25]2 years ago
4 0

Answer:

Step-by-step explanation:

<em>The linear equation where:</em>

\large \boldsymbol {}  \sf y=\underbrace{m}_{slope }x \ +\underbrace{b} _{y -intersept}

Solution :

\displaystyle \sf \#13. \\\\   6x-3y=8 \\\\\ -3y=8-6x \\\\y=-\frac{8-6x}{3}  \\\\ \boxed{\sf y=2x-2\frac{1}{3} }} \\\\ slope =2 \\\\ y-intersept  =-2\frac{1}{3} \\\\-------------      

 \sf \#14 . \\\\\\ 7x=5y+2 \\\\5y=7x-2 \\\\y =\dfrac{7x-2}{5}  \\\\ \boxed{\sf y=1,4x-0,4} \\\\slope = 1,4 \\\\y-intersept  =-0,4 \\\\---------------  

    \dispalystye \sf \#15. \\\\ -6y+4x=8  \  |\div2 \\\\-3y+2x=4 \\\\ y=-\dfrac{4-2x}{3}  \\\\ y=\boxed{\sf \frac{2x-4}{3} } \\\\slope = \dfrac{2}{3}  \\\\ y-intersept  = -\dfrac{4}{3 }\\\\ -----------------

\sf \#16   .\\\\ x+y=2x+3 \\\\y=2x-x+3 \\\\\boxed{\sf y=1\cdot x+3}  \\\\slope =1 \\\\y-intersept =3

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Answer:

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Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

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\implies \sf \cos(KLM)=\dfrac{8}{15.2}

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\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

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\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

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2 years ago
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