The mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.
Volume = 45.0 L
Temperature = = (87.0 + 273) K = 360 K
Pressure = 950 mm Hg (1 mm Hg = 0.00131579 atm) = 1.25 atm
The formula used to calculate moles is as follows.
∴PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into the above formula as follows:
∴ PV = nRT
=> 1.25 atm × 45.0 L = n × 0.0821 L atm/mol K × 360K
=> n = 1.25 atm × 45.0 L / n × 0.0821 L atm/mol K × 360K
=> n = 56.25 / 29.556 mol
=> n = 1.90 mol
Moles is the mass of a substance divided by its molar mass. So, the mass of Cl₂ (molar mass = 70.906 g/mol) is calculated as follows:
∴ Moles = mass / molar mass
=> 1.90 mol = mass / 70.906 g/mol
=> mass = 134.7214 g
Thus, we can conclude that the mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.
To know more about the Ideal Gas Law :
brainly.com/question/28976906
