Please help me i will mark as brainliest

Mathematics

1 answer:

Bingel [31]2 years ago

3 0

6. P = 2
Q = -5

7. C = -1

8. K = 3

9. A) y = 2x + 2
B) y = -3x + 5
C) y = 0x + -5

10. Y = 5x + -18

11. A)
i) (5, 0)
ii) (0, 5)

B) y = -1x + 0

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If the interval (a, infinity) describes all values of x for which the graph of f(x)=4/x^2-6x+9 is decreasing, what is the value

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Answer:

The answer is "3".

Step-by-step explanation:

$\texttt{Given graph equation: } \\\\\bold{\Rightarrow f(x)=\frac{4}{x^2-6x+9} }$

$\bold{\ interval: (a,\infty)}$

differentiate the function f(x):

$\Rightarrow f'(x) = \frac{d }{dx}(\frac{4}{x^2-6x+9})\\\\$

Formula:

$\bold{\frac{d}{dx} \frac{v}{u}= \frac{u \frac{d}{dx} v- v\frac{d}{dx}u }{u^2}}$

$\Rightarrow f'(x) = \frac{d }{dx}(\frac{4}{x^2-6x+9})\\\\\\\Rightarrow f'(x) = \frac{d }{dx}(\frac{(x^2-6x+9) \frac{d}{dx} 4- 4\frac{d}{dx}(x^2-6x+9) }{(x^2-6x+9)^2})\\\\\\\Rightarrow f'(x) = \frac{d }{dx}(\frac{(x^2-6x+9) \times 0 - 4(2x-6) }{(x^2-6x+9)^2})\\\\\\\Rightarrow f'(x) = \frac{- 4(2x-6)}{(x^2-6x+9)^2}\\\\\\\Rightarrow \frac{- 4(2x-6)}{(x^2-6x+9)^2}=0\\\\\Rightarrow - 4(2x-6)=0\\\\\Rightarrow 8x-24=0\\\\\Rightarrow 8x=24\\\\\Rightarrow x=\frac{24}{8}\\\\\Rightarrow x=3\\\\$