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kati45 [8]
3 years ago
7

Is distilled water homogeneous or heterogeneous?

Chemistry
1 answer:
Rama09 [41]3 years ago
4 0
It is neither, it is a pure substance.
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C-12, c-13, and c-14 have the same number of protons but different numbers of neutrons so they are
laiz [17]
Atoms with the same number of protons, but different numbers of neutrons are isotopes of the same element.
6 0
3 years ago
The FDA recommends that women who are pregnant avoid eating more than three 6.00-oz servings of bluefish per month because of th
Brilliant_brown [7]

Answer:

A pregnant woman would consume  1.812 x 10⁻⁶ oz of mercury in a month if she ate the maximum recommended amount of fish.

Explanation:

0.302 oz mercury _____________ 1 x 10⁶ oz bluefish

              x              _____________  6.00 oz bluefish

x = 1.812 x 10⁻⁶ oz mercury

A pregnant woman would consume  1.812 x 10⁻⁶ oz of mercury in a month if she ate the maximum recommended amount of fish.

4 0
3 years ago
Read 2 more answers
Please please help :(
Bad White [126]

Answer: ¹²₅C

Explanation:

¹²₅C is incorrect. The superscript is the atomic mass. This varies between each element. The subscript is the atomic number. This doesn't change. You will see every element has the correct atomic atomic number except for Carbon. Carbon should have atomic number 6.

7 0
3 years ago
Three places you could find alkaline earth compounds are
tatuchka [14]

Answer:

1. Soil

2. Fresh water

3. Bones and teeth

Explanation:

5 0
3 years ago
131i has a half-life of 8.04 days. assuming you start with a 1.53 mg sample of 131i, how many mg will remain after 13.0 days ___
inn [45]
For this problem we can use half-life formula and radioactive decay formula.

Half-life formula,
t1/2 = ln 2 / λ

where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days

Hence,         
8.04 days    = ln 2 / λ                         
λ   = ln 2 / 8.04 days

Radioactive decay law,
Nt = No e∧(-λt)

where, Nt is amount of compound at t time, No is amount of compound at  t = 0 time, t is time taken to decay and λ is radioactive decay constant.

Nt = ?
No = 1.53 mg
λ   = ln 2 / 8.04 days = 0.693 / 8.04 days
t    = 13.0 days 

By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg

Hence, mass of remaining sample after 13.0 days = 0.499 mg

The answer is "e"

8 0
3 years ago
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