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skad [1K]
2 years ago
11

What is a common use of bases?

Chemistry
1 answer:
Fittoniya [83]2 years ago
3 0

A common use of bases is to reduce indigestion. Hence, option D is correct.

<h3>What is the base?</h3>

A base is a substance that can neutralize the acid by reacting with hydrogen ions.

Bases are substances whose solutions have a pH value of more than 7. Bases are bitter in taste.

Whereas acids are the substances whose solutions have a pH value of less than 7. Acids are sour in taste.

When an excess of acid is formed in the human stomach then an antacid tablet which is basically a base is consumed that helps in reducing indigestion.

Therefore, we can conclude that the common use of bases is to reduce indigestion.

Learn more about the base here:

brainly.com/question/1432645

#SPJ1

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If you pour water into a hot metal pan, the water will absorb heat energy from the pan. Will the water come to the same temperat
Marina CMI [18]

Answer:

Yes

Explanation:

It is heating up both

4 0
2 years ago
Copper(II) sulfate pentahydrate, CuSO4 ·5 H2O, (molar mass 250 g/mol) can be dehydrated by repeated heating in a crucible. Which
prohojiy [21]

Answer:

The water lost is 36% of the total mass of the hydrate

Explanation:

<u>Step 1:</u> Data given

Molar mass of CuSO4*5H2O = 250 g/mol

Molar mass of CuSO4 = 160 g/mol

<u>Step 2:</u> Calculate mass of water lost

Mass of water lost = 250 - 160 = 90 grams

<u>Step 3:</u> Calculate % water

% water = (mass water / total mass of hydrate)*100 %

% water = (90 grams / 250 grams )*100% = 36 %

We can control this by the following equation

The hydrate has 5 moles of H2O

5*18. = 90 grams

(90/250)*100% = 36%

(160/250)*100% = 64 %

The water lost is 36% of the total mass of the hydrate

8 0
3 years ago
What pressure is exerted by 932.3 g of CH4 in a 0.560 L steel container at 136.2 K?
Roman55 [17]
Molar mass CH4 = 16.0 g/mol

* number of moles:

932.3 / 16 => 58.26875 moles

T = 136.2 K

V = 0.560 L

P = ?

R = 0.082

Use the clapeyron equation:

P x V = n x R x T

P x 0.560 =  58.26875 x 0.082 x 136.2

P x 0.560 = 650.76

P = 650.76 / 0.560

P = 1162.07 atm
5 0
3 years ago
Help in chem please!!!!!!
IgorLugansk [536]

This is a one-step unit analysis problem.  Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.

1 mole is equal to 6.022x10²³ particles as given, so:

1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}

<h3>Answer:</h3>

2.49 mol

Let me know if you have any questions.

3 0
3 years ago
Ne, Ar, and Kr have which properties in common? Group of answer choices
jasenka [17]

Answer:

Ne, Ar, and Kr are gases at STP, unreactive, and are generally monatomic.

Explanation:

they are unreactive and monoatomic and thats why have a very low boiling point.

6 0
3 years ago
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