Answer:
8 of the electrons will be valence electrons
Explanation:
<u> </u> The pH of 0.035 M aqueous aspirin is 2.48
<u>Explanation:</u>
We are given:
Concentration of aspirin = 0.035 M
The chemical equation for the dissociation of aspirin (acetylsalicylic acid) follows:

<u>Initial:</u> 0.035
<u>At eqllm:</u> 0.035-x x x
The expression of
for above equation follows:
![K_a=\frac{[C_9H_7O_4^-][H^+]}{[HC_9H_7O_4]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BC_9H_7O_4%5E-%5D%5BH%5E%2B%5D%7D%7B%5BHC_9H_7O_4%5D%7D)
We are given:

Putting values in above expression, we get:

Neglecting the value of x = -0.0037 because concentration cannot be negative
So, concentration of
= x = 0.0033 M
- To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
= 0.0033 M
Putting values in above equation, we get:

Hence, the pH of 0.035 M aqueous aspirin is 2.48
Answer:
34.4
Explanation:
You would divide the mg by 1000 to get the number of grams.
Answer:
13.28 mol.
Explanation:
- We can use the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 1.32 atm).
V is the volume of the gas in L (V = 242.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K).
T is the temperature of the gas in K (T = 20.0° + 273 = 293.0 K).
∴ n = PV/RT = (1.32 atm)(242.0 L)/(0.0821 L.atm/mol.K)(293.0 K) = 13.28 mol.