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Semenov [28]
3 years ago
13

If ammonia were formed from Daltons simplest formula of one atom of each element what would he have concluded about the relative

masses of nitrogen and hydrogen atoms?
Chemistry
2 answers:
3241004551 [841]3 years ago
6 0

Answer:

An atom of ammonia, is composed of 1 atom of Nitrogen and 1 of hydrogen with a mass of 6

Explanation:

In his book " A New System of Chemical Philosophy" 1808 a compound of Amonia, the relative mass of Nitrogen to Hydrogen is thought to be 1 to 5

professor190 [17]3 years ago
5 0
He would hv concluded that the ratio of the masses of nitrogen to sulphur is in the ratio 1 :3
You might be interested in
What's the balanced equation for cellular respiration?
Alik [6]
<span>Correct answer is:

C_{6}H_{12}O_6+6O_{2}\Rightarrow 6CO_{2}+6H_{2}O+energy

But how to get there?

Let's start with simple explanation of what exactly is cellular respiration. 

Cellular respiration is a multistage biochemical oxidation process of organic substances when prime product is energy (ATP - adenosine triphosphate) and other are released waste products. Cellular respiration takes place even if other metabolic processes are stopped, but cellular respiration may differ in particular organism groups.Some reactions during whole process of cellular respiration are similar in all types of living organisms.

Cellular respiration is prime indication of declining living processes.Only viruses which are on the edge of living organism and chemical particle are not performing cellular respiration.But to the point :P

In cellular respiration all substrates which are in the cell might be organic, but mostly we are using sugar oxidation - glucose in the presence of oxygen. Chemical formula of sugar looks like this:

C_{6}H_{12}O_6

Oxygen is just

O_2

so for now we have just part of the equation:

C_{6}H_{12}O_6+O_{2}\Rightarrow

But what would be on the right hand side?

It's quite simple, remember equation of full combustion? If we want to burn something we need oxygen like in the equation, so the product of this equation would be carbon dioxide, water and of course energy (ATP).Carbon dioxide formula looks like this:

CO_{2}

As a reminder water formula:

H_{2}O

Full formula would look like that:

C_{6}H_{12}O_6+O_{2}\Rightarrow\ CO_{2}+H_{2}O+energy

But still as you see this equation is unbalanced, after balancing it would like that:

C_{6}H_{12}O_6+6O_{2}\Rightarrow 6CO_{2}+6H_{2}O+energy

At the end I would like to explain one more thing. Energy which has been released during this process is part of high-energy connection which might be used to perform chemical reactions in the cell or to move organism for example in muscles. We need to remember that production of ATP is not happening with 100% efficiency and part of this energy is released as heat.</span>
5 0
3 years ago
Now molecules:
MArishka [77]

Answer:

a

Explanation:

6 0
3 years ago
Determine the [OH−] of a solution that is 0.115 M in CO32−. For carbonic acid (H2CO3), Ka1=4.3×10−7 and Ka2=5.6×10−11.
lianna [129]

Answer:

[OH⁻] = 4.3 x 10⁻¹¹M in OH⁻ ions.

Explanation:

Assuming the source of the carbonate ion is from a Group IA carbonate salt (e.g.; Na₂CO₃), then 0.115M Na₂CO₃(aq) => 2(0.115)M Na⁺(aq) + 0.115M CO₃²⁻(aq). The 0.115M CO₃²⁻ then reacts with water to give 0.115M carbonic acid; H₂CO₃(aq) in equilibrium with H⁺(aq) and HCO₃⁻(aq) as the 1st ionization step.

Analysis:

            H₂CO₃(aq)     ⇄     H⁺(aq)    +    HCO₃⁻(aq); Ka(1) = 4.3 x 10⁻⁷

C(i)          0.115M                      0                  0

ΔC              -x                        +x                  +x

C(eq)    0.115M - x                   x                    x

            ≅ 0.115M

Ka(1) = [H⁺(aq)][HCO₃⁻(aq)]/[H₂CO₃(aq)] = [(x)(x)/(0.115)]M = [x²/0.115]M

= 4.3 x 10⁻⁷  => x = [H⁺(aq)]₁ = SqrRt(4.3 x 10⁻⁷ · 0.115)M = 2.32 x 10⁻⁴M in H⁺ ions.

In general, it is assumed that all of the hydronium ion comes from the 1st ionization step as adding 10⁻¹¹ to 10⁻⁷ would be an insignificant change in H⁺ ion concentration. Therefore, using 2.32 x 10⁻⁴M in H⁺ ion  concentration, the hydroxide ion concentration is then calculated from

[H⁺][OH⁻] = Kw => [OH⁻] = (1 x 10⁻¹⁴/2.32 x 10⁻⁴)M = 4.3 x 10⁻¹¹M in OH⁻ ions.

________________________________________________________

NOTE: The 2.32 x 10⁻⁴M  value for [H⁺] is reasonable for carbonic acid solution with pH ≅ 3.5 - 4.0.

4 0
3 years ago
5. __NH3 + __O2 &gt;&gt;&gt;&gt;&gt;__ NO +__ H20
inn [45]
2 NH3+ 2 O2 —> 2 NO+ 3 H2O
5 0
3 years ago
Wht are the trends for electronegativity and ionzation energy similar​
FinnZ [79.3K]

Answer:

Along period electronegativity and ionization energy increases.

Along group electronegativity and ionization energy decreases.

Explanation:

Along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. Thus the attraction of the atoms for valance electrons increases. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required, and electronegativity also increases.

Along group:

As we move from top to bottom in periodic table the atomic sizes increases.The electrons are added in next energy level in every next element. Thus the valance electrons farther away from the nucleus and hold of nucleus becomes weaker,  because of weak nuclear attraction atomic radii increases and electronegativity and ionization energy decreases.

3 0
2 years ago
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