What is the force that acts upon a rollercoaster after it reaches the top of the hill?

The amount of energy required to raise the temperature of one gram of water by one celsius degree is called a

Elena L [17]

The amount of energy required to raise the temperature of one gram of water by one celsius degree is called a calorie.

<h3>How can you define calorie?</h3>

In physics, we can define it as a unit of measurement that defines the amount of energy to raise the temperature of 1 gram of water by 1°C. Each material has its unique calorie, however by definition we use water as it is the lowest of all the elements.

Normally, calorimetry is directly linked with the thermal capacity that an element has to contain heat.

See more about calorie at brainly.com/question/22374134

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5 0

2 years ago

A small lead ball, attached to a 1.70-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled

Otrada [13]

Answer:

H = 54.37

Explanation:

given,

lead ball attached at = 1.70 m

rate of revolution = 3 revolution/sec

height above the ground = 2 m

$velocity = \dfrac{distance}{time}$

circumference of the circle = 2 π r

= 2 x π x 1.7

= 10.68 m

$velocity = \dfrac{3 \times 10.68}{1}$

v = 32.04 m/s

using conservation of energy

$\dfrac{1}{2}mv^2 + mgh = mgH$

$\dfrac{1}{2}v^2 + gh = gH$

$\dfrac{1}{2}32.04^2 + 9.8\times 2 = 9.8\times H$

$532.88 = 9.8\times H$

H = 54.37

the maximum height reached by the ball is equal to H = 54.37

4 0

3 years ago

an object has a length of 5.0 cm, aheight of 3.0 cm and a width of 15.0 cm. it has a mass of 24 grams. what is its density?

kondaur [170]

5x3=N
Nx15=F
Fx24=Your Awnser

5 0

3 years ago

Raindrops acquire an electric charge as they fall. Suppose a 2.4-mm-diameter drop has a charge of +18 pC, fairly typical values.

muminat

To solve this problem we will apply the concepts related to the potential, defined from the Coulomb laws for which it is defined as the product between the Coulomb constant and the load, over the distance that separates the two objects. Mathematically this is

$V = \frac{kq}{r}$