First off, mass is not measured in pounds, weight is.
But, I can still solve this for you!
1/14 * 3/4
3/56 pounds is your answer
Hope this helps!
Answer:
Its a right triangle
Step-by-step explanation:
The correct question is:
Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)
Answer:
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
Step-by-step explanation:
We need to verify that
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
We differentiate
x = c1e^(-t) + c2e^(3t)
twice in succession, and substitute the values of x, x', and x'' into the differential equation
x''- 2x' - 3x = 0
and see if it is satisfied.
Let us do that.
x = c1e^(-t) + c2e^(3t)
x' = -c1e^(-t) + 3c2e^(3t)
x'' = c1e^(-t) + 9c2e^(3t)
Now,
x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]
= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)
= 0
Therefore, the differential equation is satisfied, and hence, x is a solution.
Answer:
(3,-4) or x=3 and y= -4
Step-by-step explanation:
I'm going to solve this by substitution
We first need to get a variable by itself in one of the two equations (it doesn't matter which variable and the equation you do the work on doesn't matter either)
I'm going to solve for y in the second equation
-4x-4y=4
add 4y and subtract 4 from both sides to get
-4x-4=4y
Divide by 4 to get
-x-1=y
We can plug this value in for y into the first equation and get
4x+5(-x-1)= -8
Solve for x
4x-5x-5= -8
-x-5= -8
-x= -3
x=3
We can plug this value into one of the first two equations and solve for y
4(3)+5y= -8
12+5y= -8
5y= -20
y= -4
Therefore the solution is (3,-4) or x=3 and y= -4
