CH₄ + 2O₂ ---> CO₂ + 2H₂O
16g..................................18g×2
16g CH₄ --- 36g H₂O
5,1g CH₄ --- X
X = (5,1×36)/16
X = 11,475g H₂O
Answer:
36.8 g/mol of O
Explanation:
To find the number of grams, multiply the number of moles by the atomic mass of the element.
Oxygen has an atomic mass of 16.00.
2.3 moles O × (16.00 g O ÷ 1 mole) = 36.8 g/mol O
Hope that helps.
3, 2, 1, 6
Explanation:
To balance the chemical equation the number of atoms of each element
entering the reaction have to be equal to the number of atoms of each
element leaving the reaction, in order to conserve the mass.
In our case we have:
3 CaCl₂ + 2 Na₃PO₄ → Ca₃(PO₄)₂ + 6 NaCl
So the stoechiometric coefficients will be:
3, 2, 1, 6
Learn more about:
balancing chemical equations
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37.81%
The balanced equation for the reaction is
BaCl2 + MgSO4 ==> MgCl2 + BaSO4
So for every mole of MgSO4 consumed, 1 mole of BaSO4 should be produced. Let's calculate the molar mass of MgSO4 and BaSO4.
Atomic weight magnesium = 24.305
Atomic weight oxygen = 15.999
Atomic weight sulfur = 32.065
Atomic weight barium = 137.327
Molar mass MgSO4 = 24.305 + 32.065 + 4 * 15.999 = 120.366 g/mol
Molar mass BaSO4 = 137.327 + 32.065 + 4 * 15.999 = 233.388 g/mol
Moles BaSO4 = 0.9165 g / 233.388 g/mol = 0.003926937 mol
Mass MgSO4 = 0.003926937 mol * 120.366 g/mol = 0.472669699 g
% by mass of MgSO4 = 0.472669699 g / 1.2500 g = 0.378135759 =
37.8135759%
And since we only have 4 significant digits in our data, the result rounds to
37.81%
